Red-green colorblindness is an X-linked, recessive trait. Suppose a group of 100 female and 100 male...
Red-green colorblindness is an X-linked, recessive trait. Suppose a group of 100 female and 100 male astronauts is sent to colonize a planet. 20 of the males are colorblind. 10 of the females are colorblind, and 30 are carriers. If this population were to establish a randomly mating colony in regards to this trait, what would you predict the frequency of colorblind males to be in the population over time if it were to immediately achieve and remain in Hardy-Weinberg equilibrium?
Homework Answers
Total male = 100
Total female = 100
Color blind male (XcY) = 20
Normal male (XY) = 80
Color blind female (XcXc) = 10
Carrier females (XcX) = 30
Normal female (XX) = 60
Frequency of an allele in male population = number of alleles in males / total number of alleles in males
Frequency of X allele in male = 80 / 100x2 = 80/200 = 0.4
Frequency of Y allele in male = 100 / + 100x2 = 100/200 = 0.5
Frequency of Xc allele in male = 20 / 100x2 = 20/200 = 0.1
Frequency of X allele in female= 60x2 +30 / 100x2 = 150/200 = 0.75
Frequency of Xc allele in female = 10x2 + 30/100x2 = 50/200 = 0.25
Probability of X allele of male mating X allele of female = 0.4 x 0.75 = 0.3 XX
Probability of X allele of male mating Xc allele of female = 0.4 x 0.25 = 0.1 XXc
Probability of Y allele of male mating X allele of female = 0.5 x 0.75 = 0.375 XY
Probability of Y allele of male mating Xc allele of female = 0.5 x 0.25 = 0.125 XcY
Probability of Xc allele of male mating X allele of female = 0.1 x 0.75 = 0.075 XXc
Probability of Xc allele of male mating Xc allele of female = 0.1 x 0.25 = 0.025 XcXc
frequency of color blind males (Xc Y) is 0.125 ie 12.5% of males are color blind
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