Question

genetics there are many parts to this question each in a different photo

Extended calculation problem 1 Using PCR an RFLP was identified on the first chromosome of wild strains of Banana slugs isolated in Santa Cruz. In strain C, the fragment could be cut with EcoR1 yielding 3 kb and 4 kb bands when run on a gel. In strain E, the fragment was not cut by EcoR1, resulting in a 7 kb band run on a gel. A strain E individual that is also homozygous for the first chromosome recessive mutation day-glo (dg) (bright yellow) is discovered and crossed to strain C individual that is homozygous for the dominant normal allele of Day-glo (Dg) (green). The resulting F1 individuals from this cross are mated with strain E individuals homozygous for the dg recessive mutation (and the RFLP) and the F2 progeny are scored for the body color and PCR bands on the gel for EcoR1 digestion. Four classes of progeny are produced: class 1:51 bright yellow individuals that produce a 7 kb band on the gel; class 2: 15 bright yellow individuals that produce 7kb, 3 kb and 4 kb bands on the gel; class 3: 52 green individuals that produce 7kb, 3kb and 4kb bands; class 4: 18 green individuals that produce a 7 kb band on the gel.

Answer 1

Solution:

A) To amplify specific regions using PCR, we require common reagents such as a set of appropriate primers(forward and reverse) for the desired banana slug genome or DNA segment to be amplified, a DNA polymerase(taq DNA polymerase), a specific buffer, deoxynucleotides (dNTPs), DNA template, and sterile water. (Additional reagents like Magnesium salt Mg2+ , Potassium salt K+ etc are also essential)