In the classic paper that demonstrated the semi-conservative replication of DNA, Meselson and Stahl began by showing that DNA itself will form a band when subjected to equilibrium sedimentation. They mixed randomly fragmented E coli DNA with a solution of CsCl so that the final solution had a density of 1.71 g/ml. As shortn in Figure Q8-2, with increasing length of centrifugation at 70,000 times gravity, the DNA, which was initially dispersed throughout the centrifuge tube, became concentrated over time into a discrete band in the middle.
B. What is the buoyant density of the DNA? (The density of the solution at which DNA "floats" at equilibrium defines the "buoyant density" of the DNA.) C. Even if the DNA were centrifuged for twice as long-or even longer-the width of the band remains about what is shown at the bottom of Figure QB-2. why does the band not become even more compressed? Suggest some possible reasons to explain the thickness of the DNA band at equilibrlum.
Buoyant density centrifugation or isopycnic centrifugation or equilibrium density-gradient centrifugation uses concept of buoyancy to separate molecules in solution by their differences in density.
Buoyant density of majority of DNA is 1.7g/cm3 which is equal to density of 6M CsCl solution. Buoyant density of DNA changes with its GC content( Guanine Cytosine content).
In Meselson and Stahl's method, centrifugal force pushing the particles down equals the force of the solution pushing up, causing particles to stop moving in the solution. The particles do not reach the bottom of the tube. So. the density of DNA molecules was determined based on where they reached equilibrium and stopped moving.
In their method, placement of bands depended on the density of DNA. Heavy and light DNA formed separate distinct bands with heavier DNA further down the density gradient.
The width of the band is inversely proportional to the centrifugal force.
The width of the band relates to the molecular weight and mean density of the molecules in that band. Since Mesleson and Stahl knew the approx molecular wt of their DNA molecules, they used bandwidth to calculate the density of the DNA molecle.
Since molecular weight and mean density of the E coli will have one particular value, so the width of the lower most band will become constant after a specific time period. Density of DNA in bottom most would have reached the mean density of E coli DNA molecule.That would be the heaviest DNA molecule in E coli. So, width of the band becomes constant corresponding to the heaviest molecule.
In the classic paper that demonstrated the semi-conservative replication of DNA, Meselson and Stahl began by...
JO 8-9 In the classic paper that demonstrated the semi-con- servative replication of DNA, Meselson and Stahl began by showing that DNA itself will form a band when subjected to equilibrium sedimentation. They mixed randomly frag- mented E. coli DNA with a solution of CsCl so that the final solution had a density of 1.71 g/ml. As shown in Figure Q8-2, with increasing length of centrifugation at 70,000 times gravity, the DNA, which was initially dispersed throughout the centrifuge tube,...
Question 7 (1 point) Saved DNA replication occurs through the semi-conservative replication mechanism; what was observed in the Meselson and Stahl experiment, in which DNA purified from E. coli growing on 14N-medium was centrifuged in a density gradient tube, by the third generation of DNA replication? One band representing "light" DNA OTwo bands: a light density band and a faint hybrid density band Three bands: one each of light density, hybrid density, and high density bands One band representing "heavy"...
Draw and describe the results of the Meselson-Stahl experiments showing that DNA replication followed the Semi-conservative model. Draw and describe the results if DNA replication turned out to follow the Conservative model.
Please need help answering question A the pages of background information are posted thanks Read page 196-197 and figure 6.20. regarding Meselson and Stahl’s experiment regarding DNA replication. And Answer the following question If you are using this radioactive technique in mouse cells, what would happen in each phase of G1, S, G2, mitosis and meiosis assuming that you are grown cells in 15N medium for many generations and cells in G1are then switched to 14N medium? G1 S G2...