Answer)
Yes, this is possible that one locus is in Hardy Weinberg equlibrum and other locus is not in Hardy Weinberg equlibrum.
Answer)
This is possible because one locus is selected in the population and another selection do not experience any selection.
15 IULYA Q: Can one locus be in Hardy-Weinberg proportions, and the other not? Q: Why...
4. The Hardy-Weinberg Principle. For a single locus, if the frequency of one allele (allele A) is 0.4, the frequency of the other allele (allele B) is 0.6, what are the expected frequencies of the AA genotype, the AB genotype and the BB genotype in the next generation? What are the eight assumptions that should be met when making the genotype frequency predictions? How do the eight assumptions serve to form a null model for evolution? Finally, how does one...
Give the Hardy–Weinberg expected genotypic frequencies for an autosomal locus with three alleles, where the frequencies of alleles A1, A2, and A3 are defined as p, q, and r, respectively. Set the problem up and show your work. Tay–Sachs disease is an autosomal recessive disorder. Among Ashkenazi Jews, the frequency of Tay–Sachs disease is 1 in 3600. If the Ashkenazi population is mating randomly for the Tay–Sachs gene, what proportion of the population consists of heterozygous carriers of the Tay–Sachs...
11. Which of the following hypothetical populations is in Hardy-Weinberg equilibrium at the A locus? In each case, population size is 100, and numbers refer to observed numbers of each genotype. 1.36 AA, 48 Aa, 16 aa 2. 25 AA, 50 Aa, 25 aa 3. 1 AA, 18 Aa, 81 aa 4.40 AA, 20 Aa, 40 aa A. 1 and 3 B. 2 and 4 C. 1, 2, and 3 D. 4 only E. 1,2,3, and 4
Question 13 2 pts The Hardy-Weinberg equation is p+2pq+q?-1. In a case where one allele represented by pis completely dominant to the other allele represented by q, the term 2pa represents the heterozygotes hemizygotes homozygous for the recessive trait homozygous for the dominant trait Question 14 2 pts If q=2. then 2pg equals 0.16 O 0.8 O 0.32 0 0.04
Consider a population with two autosomal alleles A, a, in Hardy-Weinberg equilibrium Let p and q be the allele frequencies of A and a, respectively 5. For what values ofp does the population contain more heterozygotes than any other genotype? Show all your working
1. According to the Hardy-Weinberg theorem, p + q = 1 and p2 + 2pq +q2 = 1. What does each of these formulas mean (how are they derived)?
Please show every step, thank you! The Hardy-Weinberg law in genetics says that the proportions of genotypes AA, Aa and aa are ?, 20(1-0), and (1-0), respectively with ? e [0,1]. Suppose that in a sample of n observations from the population, we observe ?1 individuals of type AA z2 individuals of type Aa, and x3 individuals of type aa. (a) Give the pmf of distribution of the counts X -(Xi, X2, Xs) [Hint: X follows a Multinomial distribution. The...
2.3 Problem 3 The Hardy-Weinberg equation is useful for predicting the percent of a hu- man population that may be heterozygous carriers of recessive alleles for certain genetic diseases. Phenylketonuria (PKU) is a human metabolic dis- order that results in mental retardation if it is untreated in infancy. In the United States, one out of approximately 10.000 babies is born with the disor- der. Approximately what percent of the population are heterozygous carriers of the recessive PKU allele? If you...
Explain why the Hardy-Weinberg formula shows that dominant phenotypes don't inherently increase in frequency in a population.
Equations: p + q=1 p2 + 2(p)(q) + q2 1) In a population with Hardy-Weinberg equilibrium, the frequency of a dominant allele for a gene is 85% (0.85) while the frequency of the recessive allele for the same gene is 15% (0.15). 0.0005 0.013 0.675 0.723 0.255 0.50 0.023 2) proportion of individuals will be homozygous recessive? 0.0005 0.013 0.675 0.723 0.255 0.50 0.023 3) proportion of individuals will be homozygous dominant? 0.0005 0.723 0.013 0.675 0.255 0.50 0.023 4)...