Question

hi please help. im having trouble with transcribing the given dna fragment!

1. A double stranded DNA has the following sequence: +1 5' GGCGGCGGCTGCCTATGCTGGCTTCAGCGTAGGCGTAC 3' coding strand TIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII 3' CCGCCGCCGACGGATACGACCGAAGTCGCATCCGCATG 5' A UUU UAUTY ser UCO Stog Transcribe the given DNA fragment (5-GGC GGA UGC CUC GGC UGG CUU AAG CGG AC 5'UTR (highlight in green) Second Letter с 3' UTR (highlight in blue Start Codon (highlight in yellow) VUC ) Stop Codon (highlight in red) Open reading frame (enter here): 3) Determine the complete amino acid sequence that would be translated from this mRNA Stop AUU AUC AUA AUG Met GUU GUC GUA GUG h) Identify the C- and N-terminus of the newly synthesized polypeptide (add C- and N-to your polypeptide in g).

Answer 1

5' CGCGGCGGCTGCCTATGCTGGCTTCAGCGTAGGCGTAC) 3' coding strand TIITTIIIIIIIIIIIIIIIIIIIIIIIII 3' CCGCCGCCGACGGATACGACCGAAGTCGCATCCGCATG 5'

1). 5’ UTR – GGCGGCGGCTGCC

2). 3’ UTR – GCGTAC

3). START CODON –ATG

4). STOP-CODON – TAG

5). OPEN READING FRAME – 5’ CTGGCTTCAGCG 3’

6). Translated mRNA – 5’ GACCGAAGUCGC 3’

7). N terminus is the 5’ GAC and the C terminus is the CGC 3’.

UTR is the untranslated region before and after the START and STOP codon. ATG (methionine) is the initiation or start codon from where the translation begins and the TAG is the stop codon where the process of translation stops. Open reading frame is the translated region or the region with translation ability. N terminus is with an amino-functional group that is guanine and   C terminus contains a carboxylic functional group that is cytosine.