Question

3) Dihybrid cross: The dark-bodied and rudimentary winged genes are on two different autosomal chromosomes. We will use this cross to determine the ratios of phenotypes in the F2 generation when there are two genes involved. 3.1) Use the following symbols to write out the cross: Male: 3 Female: 9 Dark body color (ebony) = e Wild-type body color: E or E+ Rudimentary wings- (vestigial wings= v) Wild-type wings: V or V+ 3.2) What would the cross look like if we mated a Dark-Bodied/Rudimentary winged double mutant = (ee/vv) male with a female that is wild type for both traits (E+E+/V+V+)? Place the sex of the individual (symbol) on the first set of lines and their respective genotypes in the second set. Sex: male () female (9) Genotypes 3.3) What are the gametes produced by either sex in the parental generation? Place the symbol for sex on the first set of lines and write down the gametes produced by that sex in the following set of lines, respectively. Sex: Gametes produced: 3.4) Using the gametes that you produced from the previous question, fill in the Punnett square and show the resulting offspring from the cross. Place female gametes to the left of the Punnett square and male gametes above.

Answer 1

3:2) Darktbodied /Rudimentary winged aloeble muutent male = kelur) Female Wild body color / wild type wings = E+E+/V+V+ sex male (0) female (9) Genotypes eevu X E+E+ /V+V+ Parent. Et e Vtv - FI generation sex male or 3.4) Ganates female (8) Et V+ pouf (5) male e Ete Tevt on v Etv tv

315) Fl offsprings are a result of true brooling lines of parents, in this case double mutant dark bodied / rudimentary wingool male it will type female male & female (Q) Et Et Vt Vt the o f generation will be eevu This Ere Vtv characters as of showing wild type female in their phenotype

3.6) ff cross Sem male (8) Genotypes EteVtv female (2) X EreVtv generation 317) Gametes' produced by either sex in Ff - Sex Male 667) Female (8) Gametes Etvt Etut 'Etv Etv ev evt evt male or x / Etup | Etv gametes er level ExNf E+E+Vtv Exevtv Epe V+ Vt +E+V+V+ (W ) LE+E+VEU ETERN Eterv EfeVtv & female gametes Ietevtv TeeVtv Erevu eevv 1 db Elevtu leevtv I (W) (w) ė V+ Et evtV+ eeV+V+, (dw).

3:9) from Fl following phenotypes are observed E+E+V+V+ = wild body color / wild type wings Et Eturv EteVtv Erev+&+ 9 phenotypes with wild body color (wild type wings. E+E+Vtv Etevev Ete Vtv Etevir Etertv EtEtur Eteve Etevv 3 phenotypes with wild body colos Condimentary winged ee Vtv ee Vtv ee W+Vt & 3 phenopypes with dark body color/ wild type wings Revy 1 phenotype with dark body colos / rudimentary wings. proportion of phenotypes in F2 genera is 2: 3:301. So the -tion