Question

Assignment #1 1. You have a plant with three different genes, a, b, and c. These genes are on the same chromosome and c is in the middle. The distance between a and c is 6 map units and the distance between c and bis 14 map units. You have a plant, heterozygous for all three genes as shown below: ac FFD You cross this plant in a test cross and collect 1000 progeny plants. (48 points) How many progenies would you expect for each class, listed below? (Rounded to the nearest whole number. The two genotypes of each class do not have to have the exact same number, they just have to add up to the correct number. i.e. Parentals = 536 = one parental could have 264 and the other could have 272, total of all progeny need to add up to 1000) Show all calculations to receive full credit. # of progeny Genotype + C + a + b a + + + cb a cb + + + + + b act

Answer 1

You have a plant with three different genes, a, b, and c. These genes are on the same chromosome and c is in the middle. The distance between a and c is 6 map units and the distance between c and b is 14 map units.

a__6U__c_____14U______b

(Rounded to the nearest whole number. The two genotypes of each class do not have to have the exact same number, they just have to add up to the correct number. i.e. Parentals = 536 = one parental could have 264 and the other could have 272, total of all progeny need to add up to 1000)

While performing the following cross and are told that the two genes are 6 m.u. apart.
Each 6 m.u. is the distance that will generate 6% recombination.

Among their progeny, 6 percent should be recombinant (a and c) , which is 1000-940=60.And 14 percent should be recombinant (b and c)which is 1000-860=140.

Parental is 80 percent, which is 1000-200=800.

Caluculate using this below formulae,

Map distance = % recombination = (# in SCO phenotypes + # in DCO phenotypes x 100)/(total # progeny)

Genotype	# of Progeny
+ c +
a + b
a + +
+ c b
a c b
+ + +
+ + b
a c +

Total Progeny =   1000

Since it is an assignment please do the calculations for understanding the #of progeny.