tcaggctttaattcatccgtgatctttgacgacggtaaatacgatgcagatataatacgatgaccgatgccaatcgaccgatcaaggaggcaccgaatggcgatgatggcgatgattgcgattaacgaagtggaacgcattatggcgggcattaacgaagatacccatgcgaccggcgaaaacgaaaccatttgcagctgcgcgaactttgaagaactgacccatgcgaccggccgcgaagcgacctaaaagtcgtaattacgtatcaagtcatgggccgcgggcgcccggcccactgactagactagggccgggcgcccgcggcccaccatataaataaaaaaaaaaaaaacgaggctatagctcatcaatgacct
Your job now is to copy the above DNA sequence and highlight each of the different sequence elements that are relevant to this particular gene (I suggest that you use different font backgrounds for each sequence element) and briefly explain what each of them do . Then, write the sequence of the mRNA that would be transcribed from this DNA sequence, identifying the AUG and STOP codon (I suggest that you bold and underline text this time).
Once you've established the protein-coding sequence in your mRNA, use any of the gazillion free online protein translators to upload the sequence of nucleotides between the AUG and the STOP codons to translate the nucleotide sequence into an amino acid sequence (Note: I do not mean genetic code tables that you may find online - I literally mean online translators in which you can upload a sequence of nucleotides starting with AUG, and obtain the predicted sequence of amino acids that would be translated from them). Finally, write the expected polypeptide sequence using one-letter amino acid notation (A for alanine, W for tryptophan, etc).
tcaggctttaattcatccgtgatctttgacgacggtaaatacgatgcagatataatacgatgaccgatgccaatcgaccgatcaaggaggcaccgaatggcgatgatggcgatgattgcgattaacgaagtggaacgcattatggcgggcattaacgaagatacccatgcgaccggcgaaaacgaaaccatttgcagctgcgcgaactttgaagaactgacccatgcgaccggccgcgaagcgacctaaaagtcg
Background Information How can we predict where a coding gene will be in bacteria? And can we then predict what protein will be produced? Take the DNA sequence below, for example. tcaggctttaattcatccgtgatctttgacgacggtaaatacgatgcagatataatacgatgaccgatgccaatcgaccgatcaaggaggcaccgaatggcgatgatggcgatgattgcgattaacgaagtggaacgcattatggcgggcattaacgaagatacccatgcgaccggcgaaaacgaaaccatttgcagctgcgcgaactttgaagaactgacccatgcgaccggccgcgaagcgacctaaaagtcgtaattacgtatcaagtcatgggccgcgggcgcccggcccactgactagactagggccgggcgcccgcggcccaccatataaataaaaaaaaaaaaaacgaggctatagctcatcaatgacct If you were a bacterial RNA polymerase, what sequence(s) should there be in this DNA for you to bind and begin transcribing? And if you found such sequence(s), where would you begin transcription? As a human being looking at this fragment of DNA, what type of consensus sequence(s)...
3. Below is the template DNA sequence for a short human protein: Template DNA = 3’ GCATGACTATTAATACGTGCGCTACCAGACTTGA5’ A. How many amino acids will the protein translated from this mRNA have? B. How many nucleotides in total will be transcribed but not translated? Assume that the stop codon is not part of the untranslated region.
1) The 5'-end of an mRNA has the sequence: ...GUCCCAUUGAUGCAUGAAUCAUAUGGCAGAGCCCGCUGG... What is the nucleotide sequence of the DNA template strand from which it was transcribed? 2) If this mRNA is translated beginning with the first AUG codon in its sequence, what is the N-terminal amino acid sequence of the protein that it encodes?
B) If this mRNA is translated beginning with the first AUG codon in its sequence, what is the N-terminal amino acid sequence of the protein that it encodes? can you help me solve A and B The 5'-end of an mRNA has the sequence: ...GUCCCAUUGAUGCAUGAAUCAUAUGGCAGAGCCCGCUGG... a What is the nucleotide sequence of the DNA template strand from which it was transcribed? The Standard Genetic Code AAA Lysine CAA Glutamine GAA Glutamate UAA stop AAC Asparagine CAC | Histidine GAC Aspartate UAC...
6. Using the answers to questions 2-5 and the below DNA sequence, predict the mRNA sequence, the tRNA anticodons, and the amino acid sequences (use the three letter code) that would result from it. (3 points) DNA +1 15'GICIA I G C A A CICATI I AA GG 3' 3" CA GATA C GTIGA GIA A A IICC 5 mRNA tRNA anticodons amino acids 7. You are interested in a gene that codes for a 20 amino acid-long protein. (1.5...
DNA, Genes and Protein Synthesis Activity 13: Protein Synthesis is the process by which cells produce (synthesize) proteins. An overview of the process is shown in model 2 (below). Gone 2 Gene 1 Gene 3 DNA strand3 TRANSLATION Protein Trp Gly Model 2 ACTIVITY and QUESTIONS 1. Based on the information you can gather from model 1 complete the following sentences: a. The nucleotide Adenine (A) always pairs with the nucleotide b. The nucleotide Guanine (G) always pairs with the...
Protein synthesis is a complicated process involving DNA being transcribed to RNA, which is then translated into amino acids. Complete the DNA-to-amino acid table for three consecutive codons with the appropriate nucleotides and amino acids using a codon table. Nucleotide and amino add options can be used multiple times or not at all.
1.) In which direction is RNA transcribed? 2.) Which of the two strands (A or B) serves as the TEMPLATE strand for the transcription of a mRNA that contains both a start and a stop codon? 3.) Which number (1, 2, 3, 4, or 5) best approximates the location of the -10 consensus sequence? 4.) How many amino acids long is the protein encoded by the mRNA from this DNA sequence? 5.) What is the second...
50 LAB 2 Genetics EXERCISE 10 PROTEIN SYNTHESIS Work with a partner to complete this exercise and answer the questions that follow. You will use the DNA strand from Exercise to make the protein for which it codes STEP 1 Review the imaginary strand of DNA below. Note the complementary base pairs. AGCAATCCGTCTTGG TCGTTAGG CAGAACC STEP 2 Draw the DNA strand separating down the middle las in the beginning of DNA replication STEP 3 Draw the free-floating RNA bases linking...
Please help with 4-10! DNA, Genes,and Protein Synthesis Activity 13: 2. The bases that interact with each other are called complementary bases. this definition and your answers to 1 complete the following: a. Thiamine (T) is the complementary base of b. Cytosine (C) is the complementary base of c. Adenine (A) is the complementary base of d. Guanine (G) is the complementary base of Based on 3. Shown below is the nucleotide sequence for one strand of a stretch of...