Question

A woman has type A blood that is Rh-negative. Her father, however, had type B blood that was Rh-positive. She marries a man who is AB positive, but his mother was Rh-negative.

I know that the allele for Rh positive blood is dominant (R) over the allele for Rh-negative blood (r). But I am having trouble with a 4x4 Punnett square which I am sure would be essential to solving this! I appreciate any help you could give!

1. What is the genotype of the woman?

2. what is the genotype of the man?

3. What is the probability of getting offspring with Type A blood?

4. Type A positive blood?

5. O negative blood?

6. AB negative blood?

7. Type B blood?

Answer 1

Here, 'It' allele is responsible for A type blood group and 'IB' allele is responsible for type B g blood group. Also, IA and IB allele are co-dominant with each other. Allele j' is recessive to both the alleles 'It' and 'IB'. Also, 'R' is the dominant allele responsible for Rh positive blood and ng is the Corresponding recessive allele responsible for the Rh negative blood. Genotype of the cooman = IA i rr Genotype of the man = IA IB Rr Now, Parents' Gameter! IA i ro x IA IBR (Ind) LOI RO (IPR) Produced

Punnett square : 1 ayar ir IAR I IAIA Ro J IA i Rr (A+) -ta TB i Rr (B+) IBR IAIⓇRO J (AB+) TAG I IATA | IA irr (A-) . (A*_) Iºs I*T* x 1; ms (0-2) (AB-)| (B-) @ Genotype of coa woman - I^ i to ③ Genotype of man = IA IB Ro ② probability of getting affpoing with type A blood = 4 = 1 (I a IA Rr, Iºs R, I^ I^rr, I^j m) 9 probability of getting offspoing with type A positive blood = 2 3 4 (IA IA Rr. IA j Rr)

② probability of getting affspring with type o negative blood = 0 © probability of getting offspring with type AB negative blood = 0 (IA IB ro) Ø probability of getting offspring with type B blood = 2 = t4 (I@iRo , T*; wr)