In maize (corn), assume that the genes A and B are linked and 30 map units...
In maize (corn), assume that the genes A and B are linked and 30 map units apart. If a plant of Ab/aB is selfed, what proportion of the progeny would be expected to be of ab/ab genotype?
| a. |
30% |
|
| b. |
4.5% |
|
| c. |
9% |
|
| d. |
15% |
|
| e. |
2.25% |
Homework Answers
Ans - (e) 2.25%
The distance between two genes is equal to the frequency of the recombination. The distance between A and B is 30 map unit which means 30% of the progeny will be recombinant.
Ab/aB - will produce four types of gamestes
Ab and aB are parental type (non recombinant) - 70%
ab and AB are recombinant type - 30%
Frequency of the ab gamete = 30/2 = 15%
Proportion of the progeny will have ab/ab genotype =
(15/100)(15/100) *100 = 2.25%
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