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A thin, massless rope is wrapped around a cylinder (I=MR^2/2) with radius .4m. The rope is...

A thin, massless rope is wrapped around a cylinder (I=MR^2/2) with radius .4m. The rope is attached to a hanging bag of stuff (m=.1kg). If the stuff accelerates downward at 1.0m/s^2 what is the mass of the wheel? Why is tension not the weight of the stuff?

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Answer #1

given that

a = 1 m/s^2

mass of stuff m = 0.1 kg

R = 0.4 m

according to the given situation ,we can say that

m*g - T = m*a

T = m*(g - a) = 0.1* ( 9.8-1)

T = 0.88 N

we know that

a = R * alpha      (alpha = angular acceleration)

alpha = a / R = 1/0.4 = 2.5 rad/s^2

we also know that

T = I * alpha

I = T / alpha =0.88 / 2.5

I = 0.352 kg*m^2

moment of inertia for cylinder I = M*R^2 / 2

M = 2* I / R^2

M = 2*0.352 / (0.4)^2

M = 4.4 kg

(b)

tension in rope is not equal to weight of the stuff because stuff is accelerating so

T = m*g - m*a

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