Question

Question 1 2 pts The mean hourly wage for employees in goods-producing industries is currently $24.57 (Bureau of Labor Statistics website, April, 12, 2012). Suppose we take a sample of employees from the manufacturing industry to see if the mean hourly wage differs from the reported mean of $24.57 for the goods-producing industries. A sample of 30 employees from the manufacturing industry showed a sample mean of $24.89 per hour. Assume a population standard deviation of $2.40 per hour. At a d = 0.01, what is your conclusion? Do not reject HO, since p-value < .01 Do not reject HO, since p-value >.01 Reject Ho, since p-value >.01 Reject HO, since p-value < .01

a) Compute the value of the test statistic (z-value of the sample mean). (Round to 4 decimal points)

b) What is the p-value? Round to 4 decimal points.

c) What is the hypotheses for this application?

Answer 1

Date Page Solution! Given that, X = 24.84 6= 2.40 n = 30 u= 24.57 a-ool The null and alternative hypothesis Hool = 24.57 Hall # 24.57 This is two-tailed test Test Statistis, Z = X-M 61 Jn z = 24.89-24.57 2.40 30 z = 0.73 The test statistic 2 =0.73 P-value = 2X P(Z <0.73) = 2X 0.7673 P-value = 1.5346 1.53 46 > 0.01 pavalue > &

fail to reject Ho. Conclusion; - Do not reject Ho. since p-value 0.01