Question

3. Each block on the inclined plane weighs 100 kg. (a) For what maximum angle the blocks will not slide if the coefficient of static friction between the blocks and the inclined surface is 0.2? (b) Will the inclined angle calculated in part (a) increase, decrease or remain same if the block weights increase to 200 kg each? Simply circle the right answer, no need to justify. (c) If the coefficient of static friction between block B and the surface becomes 0.1 while that between block A and the inclined surface remains at 0.2 draw the free body diagrams that you need to consider for calculating the minimum angle when (i) block B starts to slide, (ii) both blocks A and B slide. Note that the connecting cable CD cannot take compressive load but can carry tensile load. Blocks are 100 kg each. (d) Evaluate 0 for cases c(i) and (ii). (c) Space for free body diagram (a) 2 points @= (i) (b) 1 point Increase Decrease Remain same 2+3 points 0 = (ii) 0 =

Answer 1

msing po mgcose Given: M = 0.2 m= loong when angle o is maximum in this sitution block will tend to move down thus friction will oppose this motion and act against the sliding force which is masino. FBD shown above. Now mg sino is balanced by friction force. Efy=0 N=mg Cose thus f = MN = ung cose {fx =0 masinio = wong Cose tano en to = tantes of thus it is clear that inclination angle to starts sliding a block on an inclined plane only depends upon Co-efficient friction (1) of the surface. Omax = tant(0.2) = 11.3° (6) Does not change inclination angle because it depends only on Co-efficient of friction of the surface, Independent of mass of block.

"B=0.1, MA= 0.2 i) For block B starts to slide inclinationation angle o = tan (0.1)=5.710 A Magsine MagCoso MAG Cable CD will have no tension in this Case as the block B is tending to move down. magsino I

(11) for block A Now mclination angle required (Minimum) inclination angle required (Minimum) starts to slide will be NA mo Magsine magcose MAG - tas' (0.2) = 11.3° In this case block B definitely moves as the inclination angle required to block B is less. Tension in the cable will not change as both the blocks will move with same acceleration (gsine), measino med meg sose (d). (1) o= tas (06) = 5.71 o= tan! (0.2) = 11.30 (1)
i have explained throuly from basics hope you will understand easily please upvote it your positive reviews are motivates us. Thank you