Question

opened read only to prevent modification incompressibly, which because of the large strains cannot be accoun for via v = ). If the original length is L and the current length is /, volu conservation requires LA,=IA - A=A.(L/I) assuming uniform str and strain. Hence, 0x = A 4 = AS where A=1/L is a stretch ratio and is the nominal stress. If L=10 mm compare the values of our and for all / from 10.001 to 10.7 mm. 3.5 Repeat Exercise 3.4 for a rubber band, which also conserves its volume as it is extended by up to 50 % of its original length. Note, therefore, the potential difference between the Cauchy and Piola-Kirchhoff stresses. 3.6 What is the maximum shear stress, in terms of the applied loadſ and cross- sectional area A, in a uniaxially stressed structure Eqs. (3.293.36 and what is the associated angle as relative to an axial direction..? 3.7 Based on the type of analysis in Exercise 3.6, if an investigator correlates the proliferation and migration of fibroblasts in an injured tendon with the value of axial stress during the test (e.g.. no stress, nonzery but subphysiological stress, physiological stress, or supraphysiologic stress), how can one know that the mechanotransduction is induced by the exper- imentally convenient axial stress rather than the maximum shear stress given that both exist simultaneously i.e., their calculation depends only on the choice of the coordinate system introduced by the investigator)? 3.8 Write a three-page summary on the history of saphenous vein bypass Sum met in action the histological changes in the the T rulop G H J K L ..

i need help in problem 3.6 which is the first picture. the other 2 pictures are the equations that i need.

Answer 1

a Uni-anial loading: - 0 Y O=Ls Ity----4 fn=floso 190-0 Ikon - - fo=fsino RE Plane of cross-section - Plane of cross-section ② - ③ = Oblique plane o=&s= argle made by Oblique plane with the plane of cross-section is ACW. Ani= A = area of cross-section = bd | A2-2 = A' = Alcoso o → Stresses developed on plane of X- Section i.e..0 0 : Bh ( [n) 1-1=f (P8) 1-1=0 (ondri=5 = (fnin - f A, A1-1 (T)-= T (fas), = 0 [t=0 stresses developed on oblique plane i... 2-2 :- (4n) 2-2 = fn = f Coso y

(13) 2 - 2 = fs = f sine } . (om)22 = on = (x2 - floso on 6820 => low=560520— A2-2 A/Coso (Ts) 2-2 = Ts = (fs) 2-2 f sine A2-2 Alloso Ts = PA Sino cose = "13) Sinocos o to = I sinzo Tun = 5 Cos²o4 [o=ds] Te = 7 sine to Yo=0xx] o = 5xx = Normal Stress = f/A ts = Shear stress on the cross-section. " (on)max.= 0 (on) min.= 0 When . o=o.i.c..plane of 0 = go. Jean-9 Tmax. = Tmax. = -5 ((w) when (Cew) when 0=45° o=1350 F using ean. Have a Good day! Pls Live! ☺