we can easily calculate genetic equilibrium of by hardy -weinberg equation p2+2pq+q2=1 and the answer is option 2(p*=0.2 ,q*=0.8)
For the following genotypes with the indicated viabilities, what are the equilibrium allele frequencies, p* and...
The graph below depicts frequency curves of the three different genotypes for this locus at Hardy- Weinberg equilibrium across all possible allele frequencies. Based on this graph H2H2 H1H1 H1H2 Genotype frequencies 0 + P O 9 0.1 0.9 1 0.2 0.8 0.9 0.3 0.4 0.5 0.6 0.7 0.6 0.5 0.4 Allele frequencies 0.7 0.3 0.8 0.2 The relationship between genotype and allele frequencies for 3 genotypes of bighom sheep, where H1=p and H2= If the allele frequency for H1...
In the figure, p is the frequency of allele A, and is the frequency of allele a in a diploid population. Assuming no differences in fitness, pand should also be the frequencies of A gametes and a gametes produced by the adults. The A and a gametes combine during fertilization to produce diploid zygotes. If mating is random and the population is large, the proportion of offspring with each of three genotypes (AA, Aa, and aa) can be predicted using...
If the allele frequencies for a particular locus are f(A)=0.4 and f(a)=0.6, what are the expected genotype frequencies under Hardy Weinberg equilibrium? f(AA) = 0.16, f(Aa) = 0.48, f(aa) = 0.36 f(AA) = 0.25, f(Aa) = 0.5, f(aa) = 0.25 f(AA) = 0.4, f(Aa) = 0.24, f(aa) = 0.6 f(AA) = 0.8, f(Aa) = 0.4, f(aa) = 1.2 Which of the following is NOT true about genetic drift? Drift affects small populations more than large ones Drift can reduce a...
1a. What are the genotype frequencies and allele frequencies in a population with 20 AA genotypes, 25 AB genotypes, and 5 BB genotypes? 1b. What is the chance that you are a carrier for a given trait, if allele "A" is 20% and allele "a" is 80%?
Consider a locus of interest that has two alleles: A and a. A diploid individual carrying these alleles can have one of three genotypes: AA, Aa, or aa; a population will consist of some combination of AA, Aa, and aa individuals. The relatively frequency of each of these genotypes makes up the population's structure. Hardy and Weinberg independently figured out that, in the absence of forces that cause evolutionary change, the population structure will 'settle' or default to equilibrium values,...
Generation 1: p=0.6, q=0.4; population mean fitness =0.9 Generation 2: p'=0.54, q'=0.46 The genotype frequency in the first generation is: AA: 0.3 Aa: 0.5 aa: 0.2 Is the population in Hardy Weinberg Equilibrium? Show your work.
The goal of this exercise is to apply population genetics. The frequencies of AA, Aa, and aa genotypes in a chicken population are 0.2, 0.6 and 0.2 respectively. Answer the following questions and show your work supporting your answers: 2.1) [15 points] Provide the genotype and allele frequencies that will be present in the next generation if the previous population is mated to a second population that has for the genotypes AA, Aa, and aa frequencies 0.05, 0.6, and 0.35,...
The goal of this exercise is to apply population genetics. The frequencies of AA, Aa, and aa genotypes in a chicken population are 0.2, 0.6 and 0.2 respectively. Answer the following questions and show your work supporting your answers: 2.1) [15 points] Provide the genotype and allele frequencies that will be present in the next generation if the previous population is mated to a second population that has for the genotypes AA, Aa, and aa frequencies 0.05, 0.6, and 0.35,...
For a particular gene associated with a degenerative neurological disorder, you surveyed genotype frequencies in a population and found that 16 people had genotype AA, 97 had genotype Aa, 15 had genotype aa. a) Calculate the allele frequencies. b) Calculate the expected genotype frequencies under Hardy-Weinberg Equilibrium. Use the chi-square test to determine whether the observed number of people with different genotypes and expected number of people with different genotypes are significantly different (at an alpha level of 0.05). What...
A Texan population of wild turkey (Meleagris gallopavo) shows an insertion/deletion polymorphism locus with alleles + and –. Eggs of different genotypes have the following probabilities of surviving to adulthood: Genotype Viability + / + 60% + / – 70% – / – 50% Q.4) What will be the frequency of +/– heterozygotes in the adult survivors of the eggs described in the previous question? a. 0.41 b. 0.43 c. 0.45 d. 0.47 e. 0.49 f. 0.51 g. 0.53 h....