Question

Given the following truth table: inputs . 0 output F 1 0 0 1 1 0 0 1 0 0 D 0 1 1 1 1 0 1 lol 1 1 D 0 0 1 1 2 marks (1) Situpl
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Answer #1

* minterm of É are f=2(0,4;3,4,7). Fom Kompop for F. YZ x No uz 12 IN s - 2e De 2 (3) 17 NI sé 3 y z F=Jzt se ý ty z = (yz +9Assume Di & D2 ore 0.0 & Current I flows From onode to cethode. on diode replaced by short circuit. lov 355 Ji oma vo ov Is I+10v 3515 J. ovo Blok -OV By KUL 10 - 67.+07-10 20 ISI I, 2 - 4 ma. Also 10 = 57,7 Vo Vo= 10 - 57103 xulxic Von 3-3333 volt.

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