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Please help with Q2-42. If A and B are 10 CM apart, what proportion of the testcross progeny would be expected to have the ab phenotype? 3. If A a

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2. The possible phenotypes are AB, ab parental and Ab,aB recombinant. The distance between A and B is 10 cM indicates that recombinant phenotype would be 10 percent and parent phenotype would be 90 percent . There are two parental phenotypes which indicates ab would be 45percent( half of 90)

3. 80cM indicates 80 percent recombinant implies 20 percent parental. So ab would be 10 percent( half of 20).

4.It will be the same since the phenotype would be AB,aB,Ab,ab.

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