Question

X x 2, 3, 5, 9, 1 T "ก็ BD 10, 52 다 ICLK y 9, 9, 41 42 43 33 x

URGENT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

The present state is given as Y1 Y2 Y3 = 0 0 1

let Y1+ , Y2+ , Y3+ be the next states correspondint to present states Y1, Y2 and Y3.

For the T flip flop,

Let g1 represents the output of the first and gate, g2 represents the output of the second and gate, g3 represents the output of the third and gate and g4 represents the output of the fourth and gate.

Value of X is given as 1.

g1 = X . Y1 . Y3 ' = 1 . 0 . 0 = 0

g2 = X . Y2 ' . Y3 = 1 . 1 . 1 = 1

Since one of the AND gate value representing g2 is 1 and the 4 gates are followed by an OR gate, Oring all the outputs will result in 1.

This value of 1 is fed into the T flip flop and since the clock is 1, the new value of Q1 will be Q1 XOR T = 0 XOR 1 = 1

So, Q1+ = 1

For the D flip flop,

let g5 be the 1st AND gate and g6 be the 2nd AND gate.

g5 = X ' . Y2 ' . Y3 ' = 0 since X ' is itself 0.

g6 = X . Y2 ' . Y3 = 1 . 1 . 1 = 1

Since one of the AND gate value representing g6 is 1 and the 2 gates are followed by an OR gate, Oring all the outputs will result in 1.

This value of 1 is fed into the D flip flop and since the clock is 1, the new value of Q2 will be 1.

For the JK flip flop,

let g7 be the 1st AND gate and g8 be the 2nd AND gate.

Let g9 be the first OR gate and g10 be the 2nd OR gate.

g7 = Y1 ' . Y2 ' = 1 . 1 = 1

Since g7 is connected to g9 OR gate and its value is 1, then the output of g9 will also be a 1.

g8 = Y1 Y2 ' = 0

g10 = g8 OR X ' OR Y3 ' = 0 OR 0 OR 0 = 0

So, in the JK flip flop, J = g9 = 1 and K = g10 = 0.

When, clk =1 , J =1 , K = 0 , then output Y3 = 1.

Z = Y1 ' . Y2 . Y1 ' Y2 = 0 since Y2 is 0.

Therefore,

Y1 Y2 Y3 = 1 1 1

Z = 0

Thus, the answer is ( Y1, Y2, Y3, Z ) = 111, 0 which is the 8th option.