Question

Problem 10.80 Description: A life preserver is manufactured to support a m person with f of his volume out of the water. (a) If the density of the life preserver is 100 kg/m^3 and it is completely submerged, what must its volume be? Assume that the density of the... A life preserver is manufactured to support a 63 person with 17 % of his volume out of the water. Part A If the density of the life preserver is 100kg/m^3 and it is completely submerged, what must its volume be? Assume that the density of the person to be about the same as the density of water, 1000 kg/m^3. Express your answer to two significant figures and include the appropriate units. ANSWER: = Also accepted: = 1.2×10^−2 = 1.19×10^−2 SHOW ALL EQUATIONS IN ORIGINAL FORM ALL STEPS PLEASE

Answer 1

moss of the person mp = 63 kg Density of person (p = 1000kg /m² Total volume of purion V' M 68kg = 0.06 ook Total Vol of person inside is. V 0-83X0.63 m 0.05229 Density of preseruer is lous = 200 kg/m3 Volume of pieteikti v from fortellation fol pelete, we hawe, Fitte Powg fu+ 9 = (1000kg) 0.063 )/9.8 m/s) fa+10050.05229) (9.843) = (100049 )0.063 )(9. ) fo104.958N flom folle equation fol je plebetuer, we haur, Het weight of the process evg= 104.9C8N + V (res) V(9.8W/2) = 104.958N +000 /42 9800V-980V = 104.958 V/8820) = 104.968 V: 104.958 8820 = 119x10 m3 2 1-2x15² m3