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Image for A toy rocket engine is securely fastened to a large puck that can glide with negligible friction over a horizo

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Answer #1

initial velocity = Vi = 5 i^

final velocity = Vf = 6 i^ - 14 j^

time = t = 8 sec

acceleration is given as ::

a = (Vf - Vi )/t

a = ((6 i^ - 14 j^) - 5 i^) /8

a = (0.125)i^ - (1.75) j^

force is given as ::

F = ma

F = (2.6) (0.125)i^ - (1.75) j^

F = 0.325 i^ - 4.55 j^

component of force in X-direction ::

Fx = 0.325 N

component in Y-direction ::

Fy = -4.55 N

b)

magnitude of force is given as ::

F = sqrt (Fx2 + Fy2)

F = sqrt (0.3252 + (-4.55)2)

F = 4.562 N

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