A rocket is fired at an angle from the top of a tower of height h0...

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A rocket is fired at an angle from the top of a tower of height h0...

A rocket is fired at an angle from the top of a tower of height h0 = 40.0 m. Because of the design of the engines, its position coordinates are of the form

x(t) = A + B t² and y(t) = C + D t³,

where A, B, C and D are constants.

The acceleration of the rocket 3.00 s after firing is a = (7.00 i + 5.00 j) m/s². Take the origin of coordinates to be at the base of the tower.

a. Find the constants A, B, C & D in SI units.

b. At the instant after the rocket is fired, what is the magnitude of its acceleration?

c. At the instant after the rocket is fired, what is the magnitude of its velocity?

d. Give the x-component of the rocket's velocity 10.0 seconds after it is fired.

e. Give the y-component of the rocket's velocity 10.0 seconds after it is fired.

f. Consider the position vector of the rocket 10.0 seconds after it is fired. Give the x-component of the position vector, in meters.

g. Consider the position vector of the rocket 10.0 seconds after it is fired. Give the y-component of the position vector, in meters

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