What is the quickest way to solve this? I know you can make a 16
punnett square but that takes long.
Homework Answers
This problem can be solved by the probability method. First, calculate a probability for each monohybrid cross separately and then use the probability method to find the combined probability.
A) AA x aa = only one type of genotype is produced i.e. Aa
so the probability of Aa genotype = 4/4 = 1
BB x bb = also produces the same type of genotype i.e Bb
So the probability of the genotype AaBb = 1
B)Aa xAa genotype ratio is 1:2:1(AA:Aa:aa)
Probability of AA = 1/4, Probability of Aa= 2/4, probability of aa = 1/4
Bb xBb genotype ratio = 1:2:1 (BB:Bb:bb) probability of genotypes can be calculated same as Aa x Aa
The ratio of genotypes in both cases is 1:2:1 so it is not possible to get 1:1 ratio
AABB (1/4*1/4 = 1/16)
AaBB (2/4*1/4,= 2/16)
aaBB (1/4 * 1/4 = 1/16)
AABb (1/4*2/4 = 2/16)
AAbb (1/4*1/4 = 1/16)
AaBb (2/4*2/4 = 4/16)
aabb (1/4* 1/4 = 1/16)
aaBb (1/4*2/4 = 2/4)
Aabb(2/4* 1/4 =2)
genotype ratio is 1:2:1:2:1:4:1:2:2
C) Aa x aa = 2 Aa and 2 aa
Bb x bb = 2 Bb and 2bb
Possible genotypes = AaBb = 2/4 * 2/4 = 4/16
aaBb = 2/4 *2/4 = 4/16
AaBb = 2/4 * 2/4 = 4/16
aabb = 2/4 * 2/4 = 4/16
Genotype ratio = 4:4:4:4 = 1:1:1:1
D) Aa x aa =2 Aa and 2 aa
Probability of each genotype = 2/4
BB x BB = all BB probaility = 1(4/4)
Possible genotypes =
probability of AaBB = 2/4 * 4/4 = 8/16
probability of aaBB = 2/4 * 4/4 = 8/16
The ratio of the genotypes = 8:8 = 1:1
(E)AA x aa = all Aa
bb xBB = all Bb
So only one genotype is possible AaBb
C and D will give 1: 1 ratio, A and E give the only a single type of genotype.
You can also use these tricks for calculation
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