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1. The general manager of the Hilton Hotel in Sydney is evaluating an employment screening test for the front office clerical
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Answer #1

ANSWER::

1Q)

Let the events be defined as follows:
A: Clerical employee passing the test
B: Clerical employee being satisfactory

Given

  • 70% pass the test, \implies P(A) = 0.7
  • 80% employees are found to be satisfactory, \implies P(B) = 0.8
  • 70% of the satisfactory clerical employees have passes, \implies P(A\ |\ B) = 0.75

(a) Probabilities of

(i) Passing the test = P(A) = 0.7
(ii) having satisfactory performance = P(B) = 0.8
(iii) passing the test given satisfactory performance = P(A\ |\ B) = 0.75

(b) Probability of passing the test AND having satisfactory performance =

P(ANB) = P(B)*P( A B) = 0.8 *0.75 = 0.6(ANSWER)

NOTE: P(AUB) = P(A) + P(B) - P(ANB) = 0.7 +0.8 -0.6 = 0.9

(c) Probabilities of

  (i) Failing the test and having satisfactory performance =
P(ANB) = P(B) - P(ANB) = 0.8 -0.6 = 0.2

(ii)   Failing the test and having unsatisfactory performance =
P( A B ) = P(AUB) = 1- P(AUB) = 1 -0.9 = 0.1

(iii) Passing the test and having unsatisfactory performance =
P(ANB) = P(A) - P(ANB) = 0.7 -0.6 = 0.1

(iv) having unsatisfactory performance =
P(B) = 1-PB) = 1 -0.8 = 0.2

(d) Probabilities of

(i) Failing the test given they are found to have unsatisfactory performance =
A B 0.1 P( A B ) = P(BC) = 0 P(BC) 0.2 = 0.5

(ii) Failing the test given they are found to have satisfactory performance =
P( A B ) = P( A B) P(B) 0.2 _ 025 0.8

(iii) Passing the test given they are found to have unsatisfactory performance =

PAB) 0.1 P(AB) = ? P(BC -03 = 0.5   

(iv)   unsatisfactory performance given they failed the test =

P( B A ) 0.1 P(B° | 4) = P(4) 02 = 0.33

(v) satisfactory performance given they passed the test =

  P(BA) = P(BNA) 0.6 PA) 07=0.857

  (vi) unsatisfactory performance given they passed the test =

P(BºA) P(BºA) = 2 0.1 P(A) = 07 = 0.143

  (vii) satisfactory performance given they failed the test =

P(B | AC) = P(BNA) 0.2 PLAC = 0.3 = 0.

(e) The percentage of

(i) clerical employees who failed the test and prove to be unsatisfactory =

100 * PLAN B)% = 100 * 0.1 % = 10 %

(ii) clerical employees who passed the test and who prove to be satisfactory. =

100 * P(ANB)% = 100*0.6 % = 60 %      

f) Government guidelines require screening tests to achieve at least 20% for part (i) in (e) and at least 60% for part (ii) in (e). Does this test meet those government requirements?

Since the percentage in part (i) of (e) = 10 % which is LESS than 20 %, so NO this DOES NOT meet the government requirements.

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