5. The 60 kg woman, shown below, is holding the 248 kg box in equilibrium. The...
Consider the 61.0 kg mountain climber in the figure below. re V (5) Find the tension in the rope and the force that the mountain climber must exert with her feet on the vertical rock face to remain stationary (In N). Assume that the force is exerted parallel to her legs. Also, assume negligible force exerted by her arms. tension in rope force on feet N (b) What is the minimum coefficient of friction between her shoes and the ci
Consider the 54.0 kg mountain dimber in the figure below. (a) Find the tension in the rope and the force that the mountain dimber must exert with her feet on the vertical rock face to remain stationary (in N). Assume that the force is exerted parallel to her legs. Also, assume negligible force exerted by her arms. tension in rope N force on feet N (b) What is the minimum coefficient of friction between her shoes and the cliff?
3.) A 60.0 kg box is pulled by a 275 N force of tension provided by a rope pulled at an angle 30.0 degrees above the horizontal. The box moves 25.0 m horizontally as it is pulled by the rope. The coefficient of friction between the box and the ground is uk-0.20 a.) How much work does the rope do on the box? (5 pts) b.) How much work does friction do on the box? (5 pts) c.) How much...
A 2 kg box is sliding towards the edge of a table. Its speed is 5 m/s and it is 75 cm from the edge. The coefficient of kinetic friction is 0.3 for the box on the surface. You apply a tension force to the left. What is the minimum amount of tension needed to apply via the rope to keep the box from sliding off the edge?
Two masses are arranged as shown in the picture below with m1 = 5.98 kg and m2 = 2.29 kg. a) What minimum coefficient of static friction would be necessary to keep the system stationary? b) When the blocks are released, m2 is observed to accelerate downward with an acceleration of 1.73 m/s2. What is the tension in the rope? c) What is the coefficient of kinetic friction between m1 and the surface? d) Frictional m2
Alkg o.lom A box with mass M=1 kg is on an incline with angle 0=30 degrees with horizon. The coefficient of friction between the box and the inclined is u=0.1. a) If the box is let go from rest, how long t=? does it take it to move distance d=1 m along the surface of the inclined? b) What minimum force f=? Perpendicular to the surface of inclined is need so that the box does not move down the inclined?...
Exercise 4 A block is attached to two ropes on opposite sides (m = 20 kg). One rope is wrapped around a bollard (angle of wrap a = 360°) and loaded by a force of S4 = 1000 N. The coefficient of static friction between the rope and the bollard is Moi = 0.2. The coefficient of friction between the block and the ground is Moz = 0.3. Determine the minimum force S3 that is required to keep the block...
5. Two crates, with masses m1 = 83 kg and m2 = 210 kg, are sitting side-by-side and at rest on a horizontal surface (they are touching). A 750-N force is exerted on m1 so that the boxes both move in the same direction. If the coefficient of kinetic friction between the boxes and the table is 0.12, find: (a) the acceleration of the boxes and (b) the contact force the boxes exert on one other. 6. A raindrop falls...
As shown in the figure below, a box of mass m = 51.0 kg (initially at rest) is pushed a distance d = 98.0 m across a rough warehouse floor by an applied force of FA = 200 N directed at an angle of 30.0° below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.) (a) work...
answer d, e, f please As shown in the figure below, a box of mass m = 60.0 kg (initially at rest) is pushed a distance d = 53.0 m across a rough warehouse floor by an applied force of FA - 248 N directed at an angle of 30.0° below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest...