Homework Answers
The overall allele frequency in the two population is 0.5, therefore p = q = 0.5. (p+q=1)
Fst = Ht - Hs /Ht, (Fst ranges between 0 to 1)
Where Ht = 2pq = 2 x 0.5 x 0.5 = 0.5 and
Hs = 0 as the size of both the populations is same and heterozygosity is 0.
Therefore, Fst = 0.5 - 0 / 0.5 = 1.
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