Question

16) For the Circuit in Figure 4, determine the Thevenin Voltage, Vw, seen by the load, R. 10. 82 uno + V 60v 75Vx Figure 4 V =ov V = 26.7V V = 60V VA= 5V None of the above 17) For the Circuit in Figure 4, determine the Thevenin Resistance, Rt, seen by the load, R. R = 1892 Ry = 4.4492 Ry=41892 R =522 None of the above 18) For the Circuit in Figure 4, determine the Norton Current, In, seen by the load, R. IN = 5mA I, = 3.33A 1x =6.67A IX = 143.5mA None of the above

Answer 1

0,02 + Ya- MYY - 60v Thevenin Voltage For Finding Thevenin Voltage open the load resistor Ry and Calculate the voltage across the open circuit terminal a&b. Vab = Vth 8.92- . 1012 + 1x av 5VX Yth Gov In the above circuit, the current through the 8.12 resistor is zero because there to open circuit by Ohms lai VIR : Here IEO . Ve=OV So the voltage across 8.5215esistor (Va) is zero. The dependent Current Source Value is 5V.So 560) - OA, OA Preans no current supplied by the dependent current source. So, the dependent Current Source is open Circuited. Now the Circuit be comes

10.2 Vith Gov ( cob oth is not found. So, na In the above circuit termine, rent in the circuit. Total GOV is appear at te Van - Vith = 60V.HE Vih=6OV 17) Thevenio Resistance RTH RTH Finding R14 independent Soures aule replaced their internal cances. Independent Voltage source internal resistance 18 zero so it is shorte In our circuit dependent Source is present. We are not able to calculate directly by using Series Parallel Combinations of resistors for these type of circuits, test salce is connected (IV Source) at the open Circuit terminals (a & b) of the circuit. and then calculate the Current supplied from IV Voltage Source. Then Rith is given by ) Rrite = = Í dag var in The Circeelt for RTH Calculation 10.2 V 8 Lowa www . va I o AY,02 .

Applying low CKCL) CECL) at node vi 4 Kirchoff's Kirch current | 01-0 (o from circuit - Vx = virl + 5CV-1) + 히스야 Y) + 501 -5 + - -o 나 V + 200 - 200 +5V-5 나이 200v - 205 2 0 | 200vi = 205 | V - 205 209) I = 1 11-20S | 10000 209 x8' | H = ¥ = L - 418.

18) Norton Current , IN For finding Alorton current, shor Norton Current, Short Coulit the load -resistor RL and then finding the current through the short cicuit (IN). 10.2 V 80- cov 0 sve Applying Kirchoffs Current law CKCL) at node V 12-60 + Svet na 0 TO 10 from Circuit Va = V2 V2-60 + 5V2 + y = 0 10 47,-240 +200 Y2 + 512 40 90912--240 =0 209 V2 = 240 240 V2 = 209 IN = 12 209 2410 2091x8 209 = 0.1435 A IN = 143.5mA

16) hevenin Voltage la) Thevenin Resistance Rith = 418.12 18) Norton Current IN = 143.5 mA Thevenin Equivalent circuit RT = 418.12. MY Vion = Gov ☺ Norton Equivalent circuit & RL Iw=143. WW Rr=4180 BRL WA Note : Thevenin Resistance (Roth) and Norton resistance Crne both we same,