Question

A loaded grocery cart of mass 50 kg starts rolling across a parking lot due to strong wind, with a constant acceleration of a = -0.18 -0.08 ſms? (1) What is the displacement vector of the cart after a time of 12.25 s? (ii) Thus, what was the distance traveled by the cart? (iii) How much work does the wind do on the cart? (iv) What is the angle between the displacement vector and the force vector?

Answer 1

m= mass of cast = 50 kg azar celeration of inst 60.187 _ 0.08 2 ) mis S ha hime =12-25 sec from equation of motion inrector form 8=ut that? 3= 0+31-00189 -0.08 À ) x (12-25) 2 - 13:51 9 – 6 )m v Displacement Neclos = = 13-519-6 â )om ;;) cast moves in straight line so Distance traveled by the cas = magnihale of displacement =15) = 13512+62 = 14.78 m in worsedone by wind on the cast air -mas3 =50 (-0.185-00089) • (-)3.517627 = 121059 + 24 = 145.59 7 Die blalement vechor (3) is Busallel to sone vector C²=mag Angle blo.die plasement veltor and foole vector = 0 = 80 D.