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A lens located in the y-z plane at x = 0 forms an image of an...

A lens located in the y-z plane at x = 0 forms an image of an arrow at x = x2 = 129.3 cm. The tip of the object arrow is located at (x,y) = (x1, y1) = (-55.4 cm, 2.55 cm). The index of refraction of the lens is n = 1.4.

h26_converging

1.) What is flens, the focal length of the lens? If the lens is converging flens is positive. It the lens is diverging, flens is negative.

2.) What is y2, the y co-ordinate of the image of the tip of the arrow?

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Answer #1

1) We have v u 129.3 55.4 f-38.78cm 2)Y co-ordinate -129.3 55.4 2.55 5.95-h ycordinate 5.95cm

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