A lens located in the y-z plane at x = 0 forms an image of an arrow at x = x2 = 129.3 cm. The tip of the object arrow is located at (x,y) = (x1, y1) = (-55.4 cm, 2.55 cm). The index of refraction of the lens is n = 1.4.
1.) What is flens, the focal length of the lens? If the lens is converging flens is positive. It the lens is diverging, flens is negative.
2.) What is y2, the y co-ordinate of the image of the tip of the arrow?
A diverging lens located in the y-z plane at x = 0 forms an image of an arrow at x = x2 = -14.1 cm. The image of the tip of the arrow is located at y = y2 = 6.3 cm. The magnitude of the focal length of the diverging lens is 28.8 cm. light image х 1 Ay 3) A converging lens of focal length fconverging = 9.02 cm is now inserted at x = x3 = -14.36...
A lens located in the y-z plane at x = 0 forms an image of an arrow at x = x2 = 112.4 cm. The tip of the object arrow is located at(x,y) = (x1, y1) = (-45.9 cm, 4.91 cm). The index of refraction of the lens is n = 1.43.1) What is flens, the focal length of the lens? If the lens is converging flens is positive. It the lens is diverging, flens is negative.2) What is y2,...
# 1 and 2 are already done correctly, please do not solve A diverging lens located in the y-z plane at x - 0 forms an image of an arrow at x = x2 =-27.5 cm. The image of the tip of the arrow is located at y -y2 - 5 cm. The magnitude of the focal length of the diverging lens is 49.1 cm light (x2.y2) image 1) What is x1, the x co-ordinate of the object arrow?. 62.5...
The convex mirror shown in the drawing forms a virtual image of an arrow at x = x2 = 17 cm. The image of the tip of the arrow is located at y = y2 = 8.2 cm. The magnitude of the focal length of the convex mirror is 31 cm. 1.) What is x1, the x co-ordinate of the object arrow?. 2) What is y1, the y co-ordinate of the tip of the object arrow? 3) The object arrow...
A system of two lenses forms an image of an arrow at x = x3 = 57.9 cm. The first lens is a diversing lens located at x = 0 and has a focal length of magnitude f. = 12.4 cm. The second tens is located atx=27=25.8 cm and has an unknown focal length. The tip of the object arrow is located at (x,y) = (x, y) = (-36.6 cm, 12.1 cm). 1) What is xi, the x co-ordinate of...
A system of two converging lenses forms an image of an arrow as shown. The first lens is located at x and has a focal Length off, = 9.5 cm. The second lens is located at x = x2 = 52 cm and has a focal length of fx = 17.9 cm. The tip of the object arrow is located at (x,y) = x,y) (-14.2 cm, 3 cm). 1) What is x1, the x co-ordinate of image of the arrow...
A system of two converging lenses forms an image of an arrow as shown. The first lens is located at x = 0 and has a focal length of f. = 10.5 cm. The second lens is located at x = x2 = 55.3 cm and has a focal length of f2 = 18.3 cm. The tip of the object arrow is located at (x,y) = (x, y) = (-15.8 cm, 3.1 cm). 1) What is X, the x co-ordinate...
An object located 30.0 cm in front of a lens forms an image on a screen 7.80 cm behind the lens. (a) Find the focal length of the lens. cm (b) Determine the magnification (c) Is the lens converging or diverging? diverging converging
27-03 Convex Mirror The convex mirror shown in the drawing forms a virtual image of an arrow at x = x2 - 29.7 cm. The image of the tip of the arrow is located at y = y2 6.9 cm. The magnitude of the focal length of the convex mirror is 55 cm 1) What is X1, the x-coordinate of the object arrow?. cm Submit 2) What is y1, the y-coordinate of the tip of the object arrow? cm Sum...
An object is located 26.0 cm from a certain lens. The lens forms a real image that is twice as high as the object. What is the focal length of this lens? Now replace the lens used in Part A with another lens. The new lens is a diverging lens whose focal points are at the same distance from the lens as the focal points of the first lens. If the object is 5.00 cm high, what is the height...