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I'm having trouble understanding the adiabatic expansion of a perfect gas. My book gives the following graph, but I don't understand how the change in internal energy is 0 for process 1 (going from Ti,Vi to Ti,Vf). Youre expanding the gas-- would that not require work, ie: loss of internal energy? It's not like heat can be added to balance this out and keep the internal energy constant, since this is adiabatic. Why does only the temperature change (process 2) require work? My book only gives this as an explanation: "However, because the internal energy of a perfect gas is independent of the volume the mol- ecules occupy (Topic 2A), the overall change in internal energy arises solely from the second step, the change in temperature at constant volume."

U constant T. 2 T. Volume, V Figure 2E.1 To achieve a change of state from one temperature and volume to another temperature and volume, we may consider the overall change as composed of two steps. In the first step, the system expands at constant temperature; there is no change in internal energy if the system consists of a perfect gas. In the second step, the temperature of the system s reduced at constant volume. The overall change in internal energy is the sum of the changes for the two steps.

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gn. adiabatic Proces change aimu other Yatar temd in ternal iavo

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