Question

Consider the mass spectrometer shown schematically in the figure below. The magnitude of the electric field between the plates of the velocity selector is 2.20 10³ V/m, and the magnetic field in both the velocity selector and the deflection chamber has a magnitude of 0.0450 T. Calculate the radius of the path for a singly charged ion having a mass m = 2.36 10^-26 kg.

m

Answer 1

AnSCOOT!- Given 8 = 0.0451, m-2.36x10 kg ana E = 2.2x133 vim we know magnetic force F-qVB qVB = my? 91 = mv 9.B and velocity V = ElB 1) E -BIV E-Bv V=E/B so, 91= m (5) 98 = 2.36x1026x2.2 x 18 vim 16x1019 x (0.0457)² = 0.1603 m 0.16m