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VI! Chip Tool Workpiece The cutting force, Fc, acts in the direction of cutting speed, V, and Ft is perpendicular to Fc. The
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Chip Workpiece011 Draw BE LAD R & CF + BE. - LABE=& LBCF=2 Nfrom SACO, LDAC = 180° -[gotp] = go-ß LB AE = LBAC + LDA = ß d t go-ß = good from a BAE LABE = 180°- [CBA E + LAEB] 180°- [ 9F - AD = AE FED AE= Fusina (from A REB) ED= FC = Fe Cosa (from a CFB) F- Fesina + fe cose - 0 N = CD = FE FE - BE - BF BE = Fpolygon CDEF will be rectangle because all four angles will be 90 degrees. Hence side EF = CD and ED = FC

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