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Fe = E*q = 200*1.6*106-19 = 320*10^-19 N
Fb = v*B*q = 1200*0.2*1.6*10^-19 = 384*10^-19 N
1) Fe = 320*10^-19 N y
Fb = 384*10^-19 N -y
Fnet = -64*10^-19 N.....down wards
2)
1) Fe = 320*10^-19 N -x
Fb = 384*10^-19 N +x
Fnet = 64*10^-19 N.....right side
3)
1) Fe = 320*10^-19 N +y
Fb = 384*10^-19 N -y
Fnet = 64*10^-19 N.....upwards
answer is d)) 4 only
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The figure below shows, at a particular instant of time, the velocity vectors of four identical charged particles. The particles are in a uniform magnetic field directed to the right. We will assume that the particles are influenced only by the magnetic field. (a) Rank the four particles based on the magnitude of the magnetic force experienced by the particles at the instant shown in the picture, from largest to smallest. (Use only ">"orsymbols. Do...
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I know it can be done using Right Hand Rule, but don't know how
to solve it practically. Please help explain how to apply
right-hand rule actually. Thanks!
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Please tell me what I did wrong or why I got -4 thanks!
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expression for the net force per unit length due to the currents 1 and 2 on current 3. Use unit vector notation expression for the net force per unit length due to the currents 1 and 2 on current 3. Use unit vector notation We were...
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If you could please explain how you solved this problem it would
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Useful constants, e 2.72,1e 0.37, 3.14, 2 1.41, V3 1.73, In(2)-0.69, cos(r 14)-0.71 5 Points Each answers should bewithin10% - material ε, μ The figure above shows a parallel-plate waveguide of width w and height h, with a material between plates having H Ho, E-2Eo, where the E-field...