Hydroxyapatite, Ca10(PO4)6(OH)2 , has a solubility constant of Ksp = 2.34×10−59 , and dissociates according to...
Hydroxyapatite, Ca10(PO4)6(OH)2 , has a solubility constant of Ksp = 2.34×10−59 , and dissociates according to Ca10(PO4)6(OH)2(s)↽−−⇀10Ca2+(aq)+6PO3−4(aq)+2OH−(aq) Solid hydroxyapatite is dissolved in water to form a saturated solution. What is the concentration of Ca2+ in this solution if [OH−] is fixed at 1.40×10−6 M ?
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Hydroxyapatite, Ca10(PO4)6(OH)2 , has a solubility constant of Ksp = 2.34×10−59 , and dissociates according to...
Hydroxyapatite, Ca10(PO4)6(OH)2 , has a solubility constant of Ksp = 2.34×10−59 , and dissociates according to...
Hydroxyapatite, Ca10(PO4)6(OH)2 , has a solubility constant of Ksp = 2.34×10−59 , and dissociates according to Ca10(PO4)6(OH)2(s)↽−−⇀10Ca2+(aq)+6PO3−4(aq)+2OH−(aq) Solid hydroxyapatite is dissolved in water to form a saturated solution. What is the concentration of Ca2+ in this solution if [OH−] is fixed at 6.20×10−6 M ? [Ca2+]=
"Hydroxyapatite, Cao(PO)(OH),, has a solubility constant of Ksp = 2.34 x 10-59, and dissociates according to Ca,(PO...
"Hydroxyapatite, Cao(PO)(OH),, has a solubility constant of Ksp = 2.34 x 10-59, and dissociates according to Ca,(PO)(OH),(s) = 10 Ca2+ (aq) + 6 PO (aq) + 2OH(aq) Solid hydroxyapatite is dissolved in water to form a saturated solution. What is the concentration of Ca2+ in this solution if [OH-] is fixed at 6.50 x 10-M?
Hydroxylapalite. Ca_10(PO_4)_6(OH)_2, has a solubility constant of K_sp = 2.34 times 10^-59, and dissociates according to...
Hydroxylapalite. Ca_10(PO_4)_6(OH)_2, has a solubility constant of K_sp = 2.34 times 10^-59, and dissociates according to Solid hydroxylapalite is dissolved in water to form a saturated solution. What is The concentration a Ca2* in this solution if [OH^-] is somehow fixed at 6.80 times 10^-6 M?
3. Tooth enamel consists of the mineral hydroxyapatite, Cas(PO4)3OH, which has Ksp = 6.8 x 10-37....
3. Tooth enamel consists of the mineral hydroxyapatite, Cas(PO4)3OH, which has Ksp = 6.8 x 10-37. a. (10 points) Fill the in the ICE Box for the equilibrium of hydroxyapatite in water. You may use "x" or "S" for the changes. Cas(PO4)2OH(s) = 5 Ca2+ (aq) + 3 PO43- (aq) + OH- (aq) Initial Change Equilibrium b. (10 points) Write an expression for Ksp in terms of the concentrations of product. C. (10 points) Calculate the solubility of hydroxyapatite in...
Tooth enamel consists of hydroxyapatite, Ca5(PO4)3(OH) with a Ksp of 6.8x10-37. In water the has the...
Tooth enamel consists of hydroxyapatite, Ca5(PO4)3(OH) with a Ksp of 6.8x10-37. In water the has the potential break down using the reaction: Ca5(PO4)3(OH) (s) « 5Ca2+(aq) + 3PO33-(aq) + OH-(aq) Fluoride ions are added to the water to react with the Ca5(PO4)3(OH) and form the m ore tooth decay-resistant fluoride apatite, Ca5(PO4)3F (Ksp=1.0x10-60). Fluorinated water has dramatically decrease cavities in children, (a) calculate the solubility of Ca5(PO4)3(OH) in water and (b) will the Ca5(PO4)3F be more or less soluble?
Tooth enamel consists of hydroxyapatite, Ca5(PO4)3OH (Ksp = 6.8 x10-37). Fluoridated water has dramatically decreased cavities...
Tooth enamel consists of hydroxyapatite, Ca5(PO4)3OH (Ksp = 6.8 x10-37). Fluoridated water has dramatically decreased cavities among children; fluoride ion added to drinking water reacts with Ca5(PO4)3OH to form the more decay-resistant fluoroapatite, Ca5(PO4)3F (Ksp = 1 x10-60). What is the molar solubility (S) of hydroxyapatite and fluoroapatite in water? Hint: Ca5(PO4)3OH dissociates into [Ca5(PO4)3]+ and OH- ions. Select one: a. Shydroxyapatite = 8.25 x10-19; Sfluoroapatite = 1.0 x10-30 b. Shydroxyapatite = 1.0 x10-30; Sfluoroapatite = 8.25 x10-19 c. Shydroxyapatite...
a) The solubility product, Ksp, of Cd3(PO4)2 is 2.5 x 10-33. What is the solubility (in...
a) The solubility product, Ksp, of Cd3(PO4)2 is 2.5 x 10-33. What is the solubility (in g/L) of Cd3(PO4)2 in pure water? b) The solubility product of Cu(OH)2 is 4.8 x 10-20. Calculate the value of pCu2+, or -log[Cu2+], in an aqueous solution of NaOH which has a pH of 12.38 and is saturated in Cu(OH)2. c) The equilibrium constant for the formation of Cu(CN)42- is 2.0 x 1030. Calculate the value of pCu2+, or -log[Cu2+], if we were to...
Learning Goal: To learn how to calculate the solubility from Kspand vice versa. Consider the following equilibrium be...
Learning Goal: To learn how to calculate the solubility from Kspand vice versa. Consider the following equilibrium between a solid salt and its dissolved form (ions) in a saturated solution: CaF2(s)⇌Ca2+(aq)+2F−(aq) At equilibrium, the ion concentrations remain constant because the rate of dissolution of solid CaF2 equals the rate of the ion crystallization. The equilibrium constant for the dissolution reaction is Ksp=[Ca2+][F−]2 Ksp is called the solubility product and can be determined experimentally by measuring thesolubility, which is the amount...
± Solubility of Zinc Hydroxide in Basic Solution A solubility-product constant, Ksp, corresponds to a reaction...
± Solubility of Zinc Hydroxide in Basic Solution A solubility-product constant, Ksp, corresponds to a reaction with the following general format: salt(s)⇌cation(aq)+anion(aq) A formation constant, Kf, corresponds to a reaction with the following general format: metal ion(aq)+Lewis base(aq)⇌complex ion(aq) Part A When Zn(OH)2(s) was added to 1.00 L of a basic solution, 1.18×10−2 mol of the solid dissolved. What is the concentration of OH− in the final solution? Express your answer with the appropriate units [OH−] =???
Suppose the solubility product constant of calcium iodate is 6.47 x 10-6. If the concentration of...
Suppose the solubility product constant of calcium iodate is 6.47 x 10-6. If the concentration of calcium iodate is 0.45 M. What would be the concentrations of Ca2+ and IO3- at equilibrium? Would this solution form a precipitate? Is the solution unsaturated, saturated, or supersaturated? Note* Ksp = [Ca2+][IO3-]2
"Hydroxyapatite, Cao(PO)(OH),, has a solubility constant of Ksp = 2.34 x 10-59, and dissociates according to Ca,(PO)(OH),(s) = 10 Ca2+ (aq) + 6 PO (aq) + 2OH(aq) Solid hydroxyapatite is dissolved in water to form a saturated solution. What is the concentration of Ca2+ in this solution if [OH-] is fixed at 6.50 x 10-M?
Hydroxylapalite. Ca_10(PO_4)_6(OH)_2, has a solubility constant of K_sp = 2.34 times 10^-59, and dissociates according to Solid hydroxylapalite is dissolved in water to form a saturated solution. What is The concentration a Ca2* in this solution if [OH^-] is somehow fixed at 6.80 times 10^-6 M?
3. Tooth enamel consists of the mineral hydroxyapatite, Cas(PO4)3OH, which has Ksp = 6.8 x 10-37. a. (10 points) Fill the in the ICE Box for the equilibrium of hydroxyapatite in water. You may use "x" or "S" for the changes. Cas(PO4)2OH(s) = 5 Ca2+ (aq) + 3 PO43- (aq) + OH- (aq) Initial Change Equilibrium b. (10 points) Write an expression for Ksp in terms of the concentrations of product. C. (10 points) Calculate the solubility of hydroxyapatite in...
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