"Hydroxyapatite, Cao(PO)(OH),, has a solubility constant of Ksp = 2.34 x 10-59, and dissociates according to Ca,(PO...
Hydroxyapatite, Ca10(PO4)6(OH)2 , has a solubility constant of Ksp = 2.34×10−59 , and dissociates according to Ca10(PO4)6(OH)2(s)↽−−⇀10Ca2+(aq)+6PO3−4(aq)+2OH−(aq) Solid hydroxyapatite is dissolved in water to form a saturated solution. What is the concentration of Ca2+ in this solution if [OH−] is fixed at 6.20×10−6 M ? [Ca2+]=
Hydroxyapatite, Ca10(PO4)6(OH)2 , has a solubility constant of Ksp = 2.34×10−59 , and dissociates according to Ca10(PO4)6(OH)2(s)↽−−⇀10Ca2+(aq)+6PO3−4(aq)+2OH−(aq) Solid hydroxyapatite is dissolved in water to form a saturated solution. What is the concentration of Ca2+ in this solution if [OH−] is fixed at 1.40×10−6 M ?
Hydroxylapalite. Ca_10(PO_4)_6(OH)_2, has a solubility constant of K_sp = 2.34 times 10^-59, and dissociates according to Solid hydroxylapalite is dissolved in water to form a saturated solution. What is The concentration a Ca2* in this solution if [OH^-] is somehow fixed at 6.80 times 10^-6 M?
3. Tooth enamel consists of the mineral hydroxyapatite, Cas(PO4)3OH, which has Ksp = 6.8 x 10-37. a. (10 points) Fill the in the ICE Box for the equilibrium of hydroxyapatite in water. You may use "x" or "S" for the changes. Cas(PO4)2OH(s) = 5 Ca2+ (aq) + 3 PO43- (aq) + OH- (aq) Initial Change Equilibrium b. (10 points) Write an expression for Ksp in terms of the concentrations of product. C. (10 points) Calculate the solubility of hydroxyapatite in...
Solubility Product Ksp for Ca(OH)2 is determined in two separate experiments, both at the same temperature. - by titration of hydroxide in a simple saturated solution of Ca(OH)2. - by titration of hydroxide in a 0.01 M CaCl2 solution saturated with Ca(OH)2. Identify which of the following statements is either completely "True" or at least partially "False" (assuming that the activity of each ion is equal to its molar concentration in each instance): a) True False You would expect the value...
calculate the initial pH of the solution given the following reaction. Ca(OH)2 -> Ca2+ + 2OH- with ksp= 1.3 x 10^-6 please explain how you got your answer. 15) (5 pts) Calculate the initial pH of the solution given the following reaction and equilibrium information below: Ca(OH),(s) = Ca2+ (aq) + 20H- (aq) with Ksp = 1.3 x 10-6 A) 8.2 B) 10.3 C) 11.8 D) 12.1 E) None of these are correct + Ann
13. Calculate the value for the equilibrium constant, Ksp for the following reaction. Ca(OH)2 (s) - > Cat? (aq) + 2OH(aq) assume that a 20.00 mL sample of saturated Ca(OH)2 was titrated with a 0.050 M standard HCI solution to the equivalence point. Assume that 8.1 mL of standard HCl was needed to get to the equivalence point
1-4 please help 7 points possible Last Name First Name 1 x 1031. It dissociates in water The slightly soluble salt fluorapatite, Cas(POa)3F, has a Ksp according to the following equation: Cas(PO4)3Fi 5Ca2 3PO F 1. Write the Ksp equation for this process: Ksp Calculate the equilibrium concentrations of Ca, PO, and F. 2. a. [Ca2]= b. [PO]= c. [F]= How many grams of fluorapatite will dissolve in 1L of water? 3. 4. The solubility of the related salt hydroxyapatite,...
Learning Goal: To learn how to calculate the solubility from Kspand vice versa. Consider the following equilibrium between a solid salt and its dissolved form (ions) in a saturated solution: CaF2(s)⇌Ca2+(aq)+2F−(aq) At equilibrium, the ion concentrations remain constant because the rate of dissolution of solid CaF2 equals the rate of the ion crystallization. The equilibrium constant for the dissolution reaction is Ksp=[Ca2+][F−]2 Ksp is called the solubility product and can be determined experimentally by measuring thesolubility, which is the amount...
± Solubility of Zinc Hydroxide in Basic Solution A solubility-product constant, Ksp, corresponds to a reaction with the following general format: salt(s)⇌cation(aq)+anion(aq) A formation constant, Kf, corresponds to a reaction with the following general format: metal ion(aq)+Lewis base(aq)⇌complex ion(aq) Part A When Zn(OH)2(s) was added to 1.00 L of a basic solution, 1.18×10−2 mol of the solid dissolved. What is the concentration of OH− in the final solution? Express your answer with the appropriate units [OH−] =???