Answer:
The DeBroglie wavelength (lamda) = h/p
= h/mv
Where as lamda is the wavelength,
h is planck constant ,
m is mass&
v is velocity
In the event that we have the Planck's steady equivalent(h) to 6.626 × 10-34 m2 kg/s, and the golf ball is 0.0459 kg, and the speed is 74.0 m/s, at that point
The DeBroglie wavelength = h/mv
= (6.626 × 10-34 m2 kg/s)/[{0.0459 kg)(74.0 m/s)]
= 1.950479892 × 10-34 m
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