Question

1. an enzyme is observed to approach an initial velocity of 0.1M/s as more and more [S] is added to the reaction. additionally when V0 is equal to 0.05 M/s [S] is equal to 0.6 M. based on this information what is Vmax and Km?

2. If a psrticular enzyme has a Vmax of 0.4 M/s, and a Km of 20 mM, what is V0 wjen [S] = 0.8 M?

3. We have discussed which amino acids chymotrypsin cleaves at, however, it is possible for chymotrypsin to occassionally cleave L after extended incubation times, but at a comparstively low frequency . Based on that knowledge, answer the following questions. There are 2 peptide frsgments listed. Indicate which would have higher binding affinity , and which would have the higher Km.

4. The table represents the dats we collected on flipping "squares/seconds) in class. inverting the data to make a Lineweaver Burk plot produced the graph on the right. based on the table, calculate the Vmax, then based on the equation on the right, Calculate Vmax. you will notice a discrepancy . We broke at least one assumption the MM equation needs to work. List 1 and be clear in your answer

Include units in all your answers 1) (2) An enzyme is observed to approach an initial velocity of 0.1 M/s as more and more [S] is added to the reaction. Additionally, when vo is equal to 0.05 M/s. (S) is equal to 0.6 M. Based on this information, what is Vmax and KM? Vmax: Км: 2) (2) If a particular enzyme has a Vmax of 0.4 M/s, and a Km of 20 mM, what is vo when [S] =0.8 M? (Note: you may round to the tenths place) Vo: 3) (2) We have discussed which amino acids chymotrypsin cleaves at, however, it is possible for chymotrypsin to occasionally cleave L after extended incubation times, but at a comparatively low frequency. Based on that knowledge, answer the following. There are 2 peptide fragments listed. Indicate which would have the higher binding affinity, and which would have the higher KM. AHGAFEGGA: AHGALEGGA: 4) {4} The table represents the data we collected on flipping “squares/second" in class. Inverting the data to make a Lineweaver-Burk plot produces the graph on the right. Based on the table, calculate the Vmax, then based on the equation on the right, calculate Vmax. (Note: you may round to the tenths place) You will notice a discrepancy. We broke at least I assumption the MM equation needs to work. List 1 and be clear in your answer. Flipping Squares y = 0.965x +0.0284 vo [S] vo 0.4 0.8 0.2 Lineweaver-Burke Vmax: Table Vmax: Assumption broken:

Answer 1

1. Maximum velocity is reached when all the substrate is occupied by enzyme. So, it will be 0.1 M/s.

Vmax = 0.1 M/s

Vo = Vmax (8) Kmt (8) Quelo 0.05 = 0ol (0-6) 1 Km+0.6 0.05 km 7 0.03 = 0.06 0.05 Km = 0.06 -0.03 =0.03 = 3 = 0.6 M Queze Vo = 0.4 (0-8) ho + 0) 1000 = 0.4(08) = 0.34 -0.02 +0.8 0.88 = 0.391 M/S

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