A voltaic cell is based on two lead half cells: Pb+2(aq) + 2 e- → Pb(s)...
A voltaic cell is based on two lead half cells: Pb+2(aq) + 2 e- → Pb(s) Eo = -0.13 v
One half-cell has [Pb(NO3)2] = 0.25 M and one half-cell has [Pb(NO3)2] = 0.0020 M
What is the initial potential produced by the voltaic cell. Express your answer in units of volts with 2 significant digits, but do not include the units on the submitted answer.
Homework Answers
anode : Pb----------------------- > Pb+2 (0.020 M) + 2e-
cathode : Pb+2 (0.25M) + 2e- --------------------> Pb
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overall : Pb+2 (0.25M) -------------------> Pb+2 (0.020 M)
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Ecell = 0.05916 / 2 * log [0.25 / 0.020]
Ecell = 0.032 V
answer : initial potential = 0.032 V
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