[A0]= 0.800M
[A]=0.100M
t = 54 min
K = 2.303/t log[A0]/[A]
K = 2.303/54 log0.8/0.1
= 2.303*0.9030/54 = 0.0385 min-1
K = 2.303/t log[A0]/[A]
[A] = 0.02M
0.0385 = 2.303/t log0.8/0.02
0.0385 = 2.303*1.6020/t
t= 2.303*1.6020/0.0385 = 95.82 min >>>>> answer
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