A solution reaches a concentration of 0.014 molar N2 in water. What is the applied pressure...
A solution reaches a concentration of 0.014 molar N2 in water. What is the applied pressure in torr of the gas? (Use 6.25*10-4 M/atm as the Henry's law constant kH for N2)
Homework Answers
Calculate the applied pressure as follows:
M = kH*P
Then, P = 0.014/(6.25*10^-4)
P = 22.4 atm
Using, 1 atm = 760 torr
Then, P = 22.4*760 = 17024 torr
Therefore, the required answer is 17024 torr.
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