base millimoles = 66.8 x 0.140 = 9.352
acid millimoles = 0.3800 x 26.5 = 10.07
acid millimoles are left = 10.07 -9.352 = 0.718
[H+] = 0.718 / (66.8 + 26.5) = 7.70 x 10^-3 M
pH = -log [H+]
pH = 2.11
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