Determine the mass (in grams) of N2 that will dissolve in 155 L of water that...

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Answer 1

Answer #1

According to Henry's Law , concentration of gas N2 is given by

C= KP(n2)

wher K =henry's constant = 6.1 x10^-4 M/atm

P= partial pressure =0.739 atm

hence concentration of N2 =6.1 x10^-4 M/atm*0.739 atm = 4.5079 x10^-4 M

moles of N2 present = molarity *volume = 4.5079 x10^-4 M* 155 L = 0.06987245 moles

mass of N2 = moles of N2*molar mass of N2

=0.06987245 moles*28.0134 g/mol = 1.957 g

round to 3 significant figures,

mass of N2 = 1.96 g

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thanks

Answer 2

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