Question

Data Sheet Trial 1 2 3 4 5 Table 1: Snap Circuits Capacitance Data Capacitance 1 Capacitance 2 Capacitance 3 Time (8) Time (6) Time (s) 5.86 0.85 1.75 5.26 1.31 1.84 3.04 1.18 1,44 4.48 D.91 1.45 S.56 1.00 1.40 5.78 .82 1.45 5.97 1.24 1,33 4.97 1.07 1.76 4.98 1.37 6.05 .85 1,45 5.40s 1.025 1.52s Capacitance 4 Time (s) 6.04 S.53 5.78 6.52 5.66 6.23 6.11 5,95 6.02 5.99 5.985 6 7 8 9 .88 10 Average Post-Lab Questions 1. How did the behavior of the LED differ when you added the second capacitor in Part 1? The trame the LED shayal on decreased by aprox. 80%. 2. After adding the 100 pF capacitor in Part 1, are the capacitors in series or in parallel? Use data to support your answer. Calculate the equivalent capacitance. 3. How did the behavior of the LED differ when you added the second capacitor in Part 2? 4. After adding the 470 WF capacitor in Part 2, are the capacitors in series or in parallel? Use data to support your answer. CeScience Labs, 2018 Capacitance MO S WIN » 5. The longer the light bulb is lit, the larger the capacitance. Calculate the capacitance for each circuit arrangement. Rank your capacitances in order from greatest to least based off of the average time the light bulb was lit. Does your ranking agree with your calculations? +

Capacitance 1 Part 1A

Capacitance 2 Part 2B

Capacitance 3 Part 2A

Capacitance 4 Part 2B

Answer 1

1. On time of LED decreased when one more capacitor of 100uf was added to the circuit.

2. Capacitors are in series. The data shows that On time of LED decreased. The LED remains On as long as the capacitor discharges. In series connection the equivalent capacitance decreases and charged stored on the capacitor also decreases as C = Q/V. The On time is decreased which implies the capacitors are in series.

1/Equivalent capacitance = 1/100uf + 1/470uf

Equivalent capacitance = 82.5uf

3. The On time of LED decreased as compared to Part 1 but increased as compared to Part 2. This is expected as capacitance here is less than that of Part 1 and more as compared to that of Part 2.

4. The capacitors are in parallel. In parallel the capacitance increases. Equivalent capacitance = 100uf + 470uf = 570uf. The higher the capacitance, longer time it will take to discharge and so LED will remain On for a longer period of time. This is what is observed. The On time in Part 4 is longest.

5. Capacitance in Part 1 = 470uf (capacitance value given in picture)

Capacitance in Part 2 = 82.5uf (calculated in 2.)

Capacitance in Part 3 = 100uf (capacitance value given in picture)

Capacitance in Part 4 = 570uf (calculated in 4.)

Based on data the LED was lit for the following decreasing order:

Part 4 > Part 1 > Part 3 > Part 2

T agrees with the calculated capacitance values.

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