Homework Answers
1) New mean (x bar)= 18.3 + 5 = 23.3
because adding 5 hours in every employee results in adding 5 hours in mean.
2) New standard deviation = 3.4
As we are increasing 5 hours in every employee work hours results in mean increase of 5 hours. So, adding or subtracting same number of hours in every employee does not affect on standard deviation. So, standard deviation remains same.
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Question 10 of 10 (1 point) 3.2 Section Exercise 44 The mean and standard deviation of...
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section 10.1 A variable of two populations has a mean of 45 and a standard deviation...
section 10.1
A variable of two populations has a mean of 45 and a standard deviation of 48 for one of the populations and a mean of 45 and a standard deviation of 10 for the other population. Complete parts (a) through (c). a. For independent samples of size 16 and 4, respectively, find the mean and standard deviation of x1 - x2. (Assume that the sampling is done with replacement or that the population is large enough.) The mean...
Q 3 Are employees who work more hours per week less satisfied with their job? Data...
Q 3
Are employees who work more hours per week less satisfied with
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at a company on the following variables:
Job satisfaction (measures 0 to 100)
Total hours worked per week
Coefficients
Standard Error
intercept
120.7223
16.8721
X variable 1
-1.2033
0.3188
(a)Construct a 95% confidence interval estimate of the
population mean job satisfaction for employees who works 55 hours
per week. The sample mean total hours worked...
Question 9 of 12 (1 point) 3.2 Section Exercise 3 In a distribution of 160 values...
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Question 6 of 8 (1 point) Attempt 1 of Unlimited 3.2 Section Exercise Time to review: The following table presents the time taken to review articles that were submitted for publication to a particular journal during a recent year. A few articles took longer than 6 months to review; these are omitted from the table. Consider the data to be a population. Number of Articles TA Time (Months) 0-0.9 44 16 1.0-1.9 2.0 - 2.9 3.0-3.9 17 20 4.0-4.9 12...
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section 10.1
A variable of two populations has a mean of 45 and a standard deviation of 48 for one of the populations and a mean of 45 and a standard deviation of 10 for the other population. Complete parts (a) through (c). a. For independent samples of size 16 and 4, respectively, find the mean and standard deviation of x1 - x2. (Assume that the sampling is done with replacement or that the population is large enough.) The mean...
Q 3
Are employees who work more hours per week less satisfied with
their job? Data was collected from a random sample of 22 employees
at a company on the following variables:
Job satisfaction (measures 0 to 100)
Total hours worked per week
Coefficients
Standard Error
intercept
120.7223
16.8721
X variable 1
-1.2033
0.3188
(a)Construct a 95% confidence interval estimate of the
population mean job satisfaction for employees who works 55 hours
per week. The sample mean total hours worked...
Question 9 of 12 (1 point) 3.2 Section Exercise 3 In a distribution of 160 values with a mean of 72, at least 120 fall within the interval 65-79. Approximately what percentage of values should fall in the interval 58-862 Use Chebyshev's theorem. Round your k ands values to one decimal place and final answer to two decimal places. % of data will fall between 58 and 86. Approximately
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