Question

Three point charges are located at the corners of an equilateral triangle as shown in Figure P23.7 (9 = 3.50 Âuc, L = 0.400 m). Calculate the resultant electric force on the 7.00 Âuc charge. N ° (counterclockwise from the +x axis) 7.00 uc 60.00 -4.00 uC Figure P23.7

Answer 1

briven, q=3.5 MC, L=o.4om of 7uc x 0=120° 1200 Fnet -u uc Fl=K qia 2 - - 1 UTEO x 9 x 7 uc 12 C2 fi= 9x109 Nm2 x 3.5810-6x7x10-6 c² (0.40)2 m2 Fi = 1.38N Fe = 9x109 Nm² x 4x10-6 CX78106c C2 (0.40)2 m2 F2 = 1.575N Angle between fl and fa is a = 120°, Fnet JFR + F2²+ 2 F1 F2 cso fnet (1:38)2 + (1.54s)2+2*1-38X1.545 x cos (120) [fret = t. 49 N Ans.

Angle 2014 que te use, fainaguta FU *- component of force, Fu= Fi costo of fz ws Goo Fn = (1.38+1.575) cos 60° fa a borses for 1.4775N and Fy = fa sin 60° - fi sin foo fy = (1.575 - 1.38) NX sin foo fy = 0.169N 0 = tani ( ) = tan! ( 0:46.925) o = 6.520 (Clockwise) For counter clockwise, use d'= 360-0=360° - 6.52° Lol = 353.50 counterclockwise from ta anis Ang