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5. Consider the second order equation x + x = 0 with initial conditions (0) = 1, x(0) = 0. We know the solution is x(t) = c
0 0
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Answer #1

Given problem is d2k + U=0 where , u=l, dx= 0, when tzo. dt? let dor=y. So, that d2e = dy Them we have de = yen dy -t, where,First_Aprilozimation putting nembo omo legno we get sy = 1 + 5*odt - 14[ordt - 1 - 0 30.2, 0-4*%dt = -fedt -® Second ApproximFoweth approximation - Pulting med imeno - A ugimey ogn @. 964 = 1 +f*ladt a 1+4+ + Lif3fdt H4 = 1- * hity - Putting n=4 in efrom B & eam 16 It is clear that au = 45 _so, approximation soin of given Problemen 2l = 1- 2 + 1 lies es 94

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