Homework Answers
We are trying to find a Zcritical above which the probability in a standard normal distribution is greater than 9%
P(Z > Zcritical) = 0.09
From standard normal distribution table, Zcritical = 1.35
Thus, X = mean + (std. dev.) * 1.35 = 496 + 1.35*111 = 496 + 149.85 = 645.85
Thus, 645.85 is the minimum marks that will put anyone in the top 9%
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in Test Pause Test Quiz: Chapter 6 Question 4· 1 of 24 Step 1 of 1...
suppose ACT reading scores are normally distributed with a mean of 21.4 and a standard deviation...
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suppose ACT reading scores are normally distributed with a
mean of 21.4 and a standard deviation of 5.9 . A university plans
to award scholarships to students who’s scores are in the top 9%.
what is the minimum score required for the scholarship?
Suppose ACT Reading scores are normally distributed with a mean of 21.4 and a standard deviation of 5.9. A university plans to award scholarships to students whose scores are in the top 9 %. What is the...
Suppose ACT Reading scores are normally distributed with a mean of 21.4 and a standard deviation of 5.9. A university plans to award scholarships to students whose scores are in the top 9 % . what is the minimum score required for the scholarship? Round your answer to the nearest tenth, if necessary.
Step By Step 4 of 5 Suppose ACT Reading scores are normally distributed with a mean of 21.4 and a standard deviation of 5.9. A university plans to award scholarships to students whose scores are in the top 9 % . What is the minimum score required for the scholarship? TablesKeypad we have found the value-z =-1.34, such that the area to the left of-z is approximately 0.09. Since the standard normal curve is symmetric and centered at zero, the...
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USE R COMMANDS PLEASE
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