Question

Consider the following closed system PV diagram for an ideal gas. This plot shows two isotherms and five different paths: 1 – 5.( The arrows indicates the direction each path follows).

1. Consider the following closed system PV diagram for an ideal gas. This plot shows two isotherms and five different paths: 1- 5The arrows indicates the direction each path follows). Pressure (atm) 3 T. 2 Volume (m3) Match EACH path 1-5 with one of the following descriptions and explain/jiustify vour reasoning C.QW0

Answer 1

For the paths shown, T2>T1

Path 3 is constant volume process and for constnt volume process of an ideal gas W= P*dV=0 . Q= CV*(T1-T2)

T2>T1. Q<0 ( path A)

path 5 is constanrt pressure process and for constant pressrue ( isobaric process), W=- P*(V2-V1) =-R*(T2-T1)<0

and Q=Cp*IT2-T1) > 0 ,

:Path-1 is isothermal process for which deltaU=0 , deltaU= Q-W, Q= W >0 ( since there is an increase in volume in path -1) ( D is the answer)

path 4 is heating. Q>O and deltaU= Q-W

W= Q-deltaU

W<Q

O<W<Q ( B is the correct answer)

for cooling ( path -2), Q>W>0 ( reverse of path-4). ( C is the correct answer)