Hello. I understand that you wanted all your
questions to have solved. But Chegg Expert Policy doesn't allow us
to solve more than one question. So please understand that even as
Chegg expert we have limitations too.
I have provided detailed answer but if you have doubts please ask.
I'd love to help.
It's a humble request to please upvote the answer. I really need
this help now. Please.
Have a nice day.according to HomeworkLib policy i
answered first four question.sry i can't answer
more.
Problem 1. Consider a graph G with n vertices: • Ifq is the size of the...
need help with a and b in this graph theory question
Let n >k> 1 with n even and k odd. Make a k-regular graph G by putting n vertices in a circle and connecting each vertex to the exact a) Show that for all u,v there are k internally disjoint u, v-paths (you (b) Use the previous part, even if you did not prove it, to show that the e vertex and the k 1 closest vertices on either...
7. An independent set in a graph G is a subset S C V(G) of vertices of G which are pairwise non-adjacent (i.e., such that there are no edges between any of the vertices in S). Let Q(G) denote the size of the largest independent set in G. Prove that for a graph G with n vertices, GX(G)n- a(G)+ 1.
Use induction on n...
5. Use induction on n to prove that any tree on n2 2 vertices has at least two vertices of degree 1 (a vertex of degree 1 is called a leaf).
5. Use induction on n to prove that any tree on n2 2 vertices has at least two vertices of degree 1 (a vertex of degree 1 is called a leaf).
Prove that if G is a connected graph of order n ≥ 2, then the vertices of G can be listed as v1, v2, . . . , vn such that each vertex vi (2 ≤ i ≤ n) is adjacent to some vertex in the set {v1, v2, . . . , vi−1}.
Please answer the question and write
legibly
(3) Prove that for a bipartite graph G on n vertices, we have a(G)- n/2 if and only if G has a perfect matching. (Recall that α(G) is the maximum size among the independent subsets of G.)
(3) Prove that for a bipartite graph G on n vertices, we have a(G)- n/2 if and only if G has a perfect matching. (Recall that α(G) is the maximum size among the independent subsets of...
Let G be a simple graph with 2n, n 2 vertices. Suppose there are at least n2 1 edges. Show that at least one triangle is formed. Hint: Check n 2 first and then use induction
Let G be a simple graph with 2n, n 2 vertices. Suppose there are at least n2 1 edges. Show that at least one triangle is formed. Hint: Check n 2 first and then use induction
49.12. Let G be a graph with n 2 2 vertices. a. Prove that if G has at least ("21) +1 edges, then G is connected. b. Show that the result in (a) is best possible; that is, for each n 2 2, prove there is a graph with ("2) edges that is not connected.
49.12. Let G be a graph with n 2 2 vertices. a. Prove that if G has at least ("21) +1 edges, then G is...
) A vartex cover is n set af vertices for which esch edge has at lesst ane of its vertices in the set. What is the size of the smallest vertex ㏄ver in the Petersen graph? Give an example of such a set Prove that a smaller set does not exist. A dominating sot is a set of vertices for which all other vertices have nt lenst ane neighbar in this set. What is the e of the smallest dominating...
Question 1: Given an undirected connected graph so that every edge belongs to at least one simple cycle (a cycle is simple if be vertex appears more than once). Show that we can give a direction to every edge so that the graph will be strongly connected. Question 2: Given a graph G(V, E) a set I is an independent set if for every uv el, u #v, uv & E. A Matching is a collection of edges {ei} so...
Find the logical mistakes in these proofs, and explain why the mistakes you've identified cause problems in their arguments. (b)Claim: Suppose that G is a graph on n 3 vertices in which the degree of every vertex is exactly 2. Then G is a cycle Proof. We proceed by induction on n, the number of vertices in G. Our base case is simple: for n - 3, the only graph with 3 vertices in which all vertices have degree 2...