Question

php?attempt=14457456&cmid=4092897&scrollpos=11702#q22 Status Page The following FOUR QUESTIONS refer to this scenario: When measuring the respiratory surface area of gills in brook trout, Abigail notices that the surface area grows linearly when compared to the volume of the fish as the fish grew: Respiratory surface area of gills Volume of fish Eestion 13 What relationship do the data in the graph reveal as the trout grow larger? es remaining: Foints out of 1.00 P Flag Select one: a. The ratio of gill respiratory surface area to body volume increases faster than linearly b. The ratio of gill respiratory surface area to body volume increases linearly C. The ratio of gill respiratory surface area to body volume is constant (stays the same d. The ratio of gill respiratory surface area to body volume decreases linearly e. The ratio of gill respiratory surface area to body volume decreases faster than linearly question Check Question 14 Correct Based on her data, what did Abigail conclude enabled the fish to maintain this relationship of respiratory surface area to body volume during the fish's growth? 100 points out Select one 2. As the body of the fish grows, its gill surface area has to increase much faster than predicted for the SA/V ratio of a body of the same shape se Flag

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Answer 1

Answer: C

The ratio of the respiratory surface area of gills to the volume of fish =

Respiratorysur facear ea Volumeoffish

We can see that the graph is linear. Without going to mathematics, we can think by an example.

In this example, we can see that when the value of the volume is 2 respiratory surface area of gills is 2 and when the volume of fish is 4 the respiratory surface area of gills is 4 (forget about values and units)

Respiratory Surface areal of gills at x o i 4 5 vol of 2 3 rol of fish

The ratio for the first case = $\frac{2}{2}=1$

The ratio for the second case $\frac{4}{4}=1$

We can see that even if the value of coordinates has changed, it didn't affect its ratios. it is because the graph follows the equation y=mx+c. It is linear. Meaning that as y changes x also changes in the same degree or linearly. So the y/x ratio remains the same!

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