\(\mathrm{p}=\mathrm{mv}\)
\(3 p=3 m v\)
\(\mathrm{K}=\frac{1}{2} m v^{2}\)
the mass is the same then \(v\) is increasing 3 times
\(\mathrm{K}=\frac{1}{2} m(3 v)^{2}\)
\(\mathrm{K}=\frac{1}{2} m(9) v^{2}\)
then 9 times
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